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Mumz [18]
3 years ago
6

825 tickets were sold for a game for a total of $1,462.50. If adult tickets sold for $2.50 and children's tickets sold for $1.00

, how many of each kind of ticket were sold?
Mathematics
2 answers:
Shtirlitz [24]3 years ago
7 0

Answer:

greater etext they'd hereafter greatest note count defective justification

In-s [12.5K]3 years ago
7 0
Let the number of adults tickets = a
Let the number of children’s tickets = c

Form 2 equations:

825 tickets total:
a + c = 825 (1)

Cost of tickets:
2.50a + 1.00c = 1,462.50
c = 1462.50 - 2.5a (2)

Solve equations (1) & (2) simultaneously:

Sub (2) into (1):
a + (1462.5 - 2.5a) = 825
a - 2.5a = -637.5
-1.5a = -637.5
a = 425

Sub a=425 into (1):
425 + c = 825
c = 400

Therefore 450 adults tickets and 400 children’s tickets were sold
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If Bob produces 36 or fewer items in a week, he is paid X dollars per item. If Bob produces more than 36 items in a week, he is
Greeley [361]

Answer:

How many items did Bob produce last week? 32 items.

Step-by-step explanation:

(1) Last week Bob was paid total of $480 for the items that he produced that week.

(2) This week Bob produced 2 items more than last week and was paid a total of $510 for the items that he produced this week.

a) Let's start with the simplest case:  he produced 36 or less items this week.

In this case he produced less than 36 items last week too.

So he was paid the same amount of dollar per item.

Using (1) and (2) assumptions we have:

$480+2X=$510

⇒2X=$510-$480

⇒2X=$30

⇒2X=$30/2

⇒X=$15

He was paid $15 per item.

Last week he was paid $480.

480/15= 32 items.

This week he was paid $510.

510/15=34 items.

The other cases has no solutions.

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3 years ago
Marcia has 412 flower for centerpieces.She uses 8 flowers for each centerpiece.How many centerpieces can she make?
Mkey [24]

Answer:

412/8= 51 centerpieces

Step-by-step explanation:

3 0
3 years ago
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F(x) = 3x + 6 please help quickly!!!!!!!
Georgia [21]

Given the function, <em>f(x) = 3x + 6,</em> we can solve for f(a), f(a + h) and \frac{(f(a + h) - f(a)) }{h} by substituting their values into f(x) = 3x + 6. We will have the following:

\mathbf{f(a) = 3a + 6}\\\\\mathbf{f(a + h) = 3a + 3h + 6}\\\\\mathbf{\frac{(f(a + h) - f(a)) }{h} = 6}

<em><u>Given:</u></em>

  • f(x) = 3x + 6

<em>We are told to find:</em>

  1. f(a)
  2. f(a + h), and
  3. \frac{(f(a + h) - f(a)) }{h}

1. <em><u>Find f(a):</u></em>

  • Substitute x = a into f(x) = 3x + 6

f(a) = 3(a) + 6

f(a) = 3a + 6

<em>2. Find f(a + h):</em>

  • Substitute x = a + h into f(x) = 3x + 6

f(a + h) = 3(a + h) + 6

f(a + h) = 3a + 3h + 6

<em>3. Find </em>\frac{(f(a + h) - f(a)) }{h}<em>:</em>

  • Plug in the values of f(a + h) and f(a) into \frac{(f(a + h) - f(a)) }{h}

Thus:

\frac{((3a + 3h + 6) - (3a + 6)) }{h}\\\\\frac{(3a + 3h + 6 - 3a - 6) }{h}\\\\

  • Add like terms

\frac{(3a - 3a + 3h + 6 - 6) }{h}\\\\= \frac{3h }{h}\\\\\mathbf{= 3}

Therefore, given the function, <em>f(x) = 3x + 6,</em> we can solve for f(a), f(a + h) and \frac{(f(a + h) - f(a)) }{h} by substituting their values into f(x) = 3x + 6. We will have the following:

\mathbf{f(a) = 3a + 6}\\\\\mathbf{f(a + h) = 3a + 3h + 6}\\\\\mathbf{\frac{(f(a + h) - f(a)) }{h} = 6}

Learn more here:

brainly.com/question/8161429

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