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UkoKoshka [18]
2 years ago
13

What is the end behavior of f(x) = -0.5^2 + 2

Mathematics
1 answer:
NeX [460]2 years ago
4 0

Answer:

f = 1.75\x /x

Step-by-step explanation:

Let's solve for f.

fx=−0.52+2

Step 1: Divide both sides by x.

fx

x

=

1.75

x

f=

1.75

x

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The radius of a circle is changing at the rate of 1/π inches per second. At what rate, in square inches per second, is the circl
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Answer:

10 square inches per second.

Step-by-step explanation:

The radius of the circle is given by the equation:

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Remember that the area of a circle of radius R is written as:

A = π*R^2

Then the area of our circle will be:

A(t) = π*( (1/π  in/s)*t)^2 = π*(1/π  in/s)^2*(t)^2

Now we want to find the rate of change (the first derivation of the area) when the radius is equal to 5 inches.

Then the first thing we need to do is find the value of t such that the radius is equal to 5 inches.

r(t) = 5 in =  (1/  in/s)*t

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So the radius will be equal to 5 inches after 5*π seconds, let's remember that.

Now let's find the first derivate of A(t)

dA(t)/dt = A'(t) = 2*(π*(1/π  in/s)^2*t = (2*π*t)*(1/π  in/s)^2

Now we need to evaluate this in the time such that the radius is equal to 5 inches, we will get:

A'(5*π s) = (2*π*5*π s)*((1/π  in/s)^2

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The rate of change is 10 square inches per second.

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