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2 years ago

F(x)= -2 |x-2|+ 4 vertically stretched by a factor of 2.

Mathematics

1 answer:

Veronika [31]2 years ago

6 0

Answer:

f(x) = 4x^2 +2,

is the function

Step-by-step explanation:

if i get this wrong imma tie a brick to my feet and jump in the ocean

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What is the horizontal and vertical shift for the absolute value function below?f(x) =|x-5|+1The graph shifts right 5 and up 1.T

maria [59]

The correct answer is option A;

The graph shifts right 5 and up 1

4 0

1 year ago

22. Write the equation of the line through (3, 4) and (2, 1) in slope-intercept form. (Hint: Find point-slope form first)

salantis [7]

Answer:

y = 3x - 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (3, 4 ) and (x₂, y₂ ) = (2, 1 )

m = $\frac{1-4}{2-3}$ = $\frac{-3}{-1}$ = 3 , then

y = 3x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, 1 ) , then

1 = 6 + c ⇒ c = 1 - 6 = - 5

y = 3x - 5 ← equation of line

5 0

2 years ago

A consumer agency is investigating the blowout pressures of Soap Stone tires. A Soap Stone tire is said to blow out when it sepa

Likurg_2 [28]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: Impact force needed for Sap Stone tires to blow out. (foot-pounds)

n= 29, S= 1358 foot-pound

Soap Stone claims that "The tires will blow out at an average pressure of μ= 26000 foot-pounds with a standard deviation of σ= 1020 foot-pounds.

According to the consumer's complaint, the variability of the blown out forces is greater than the value determined by the company.

Then the parameter of interest is the population variance (or population standard deviation) and to test the consumer's complaint you have to conduct a Chi-Square test for σ².

σ²= (1020)²= 1040400 foot-pounds²

H₀: σ² ≤ 1040400

H₁: σ² > 1040400

α: 0.01

II)

$X^2= \frac{(n-1)S^2}{Sigma^2} ~~X^2_{n-1}$

$X^2_{H_0}= \frac{(n-1)S^2}{Sigma^2}= \frac{(29-1)*(1358)^2}{1040400} = 49.63$

III)

This test is one-tailed to the right and so is the p-value. This distribution has n-1= 29-1= 28 degrees of freedom, so you can calculate the p-value as:

P(X²₂₈≥49.63)= 1 - P(X²₂₈<49.63)= 1 - 0.99289= 0.00711

⇒ The p-value is less than the significance level so the test is significant at 1%. You can conclude that the population variance of the blowout forces is less than 1040400 foot-pounds², at the same level the population standard deviation of the blow out forces is less than 1020 foot-pounds.

99% CI for the variance. Using the X² statistic you can calculate it as:

$[\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ]$