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antoniya [11.8K]
3 years ago
5

Solve for x: 7x = 105

Mathematics
2 answers:
stira [4]3 years ago
6 0

Answer:

<u>X=15</u>

Explanation: You have no like terms to combine and are at the last step of the algebraic equation. So, you would divide 7 on both sides. 7 by 7 cancels it out and 105 divided by 7 equals 15. Hope this helps ^-^.

ohaa [14]3 years ago
5 0

Answer:

The answer is 15 !!!

Step-by-step explanation:

Divide 105 by 7 and get 15. The answer to your question is x=15.

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Nastasia [14]

First, use distributive property on the right half.

2 * 5 = 10

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4n - 9 = 10 + 4n

Add 9 to both sides

4n = 19 + 4n

Subtract 4n from both sides

0 = 19

But thats not true. Therefore, there is no solution.

4 0
3 years ago
Direct and Indirect Proportions
ivanzaharov [21]

Answer:

?

Step-by-step explanation:

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Answer:

615.44 cm^2

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8 0
2 years ago
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Find m∠A given ΔABC where a=4, b=6, c=3.
igomit [66]
For this question, we're going to use the law of cosines.
The law of cosines is the following equation:

a^2=b^2+c^2-2(b)(c) \cos(A)

We know the values of a, b, and c. We want to find the measure of angle A.
a=4
b=6
c=3

Now, plug in these values into the equation.

4^2=6^2+3^2-2(3)(6) \cos(A)
16=45-36 \cos(A)

Add both sides by 36 \cos(A) and subtract both sides by 16

36 \cos(A)=29

Divide both sides by 36

\cos(A)= \dfrac{29}{36}

Take the inverse cosine, or arc cosine, of both sides.
Using a calculator, you'll get the following result.

A \approx 36.3^O

The measure of angle A should be 36.3 degrees. Hope this helps! :)
4 0
3 years ago
N is an integer. Prove that (2n+1)(n+3)+(2n+1)(n-2) is not a multiple of 2. thanks.
KonstantinChe [14]

Answer:

(2n + 1)(n + 3) + (2n + 1)(n - 2)

= (2n + 1)(n + 3 + n - 2)

= (2n + 1)2n + 1)

= 4n² + 4n + 1

= 2(2n² + 2n) + 1

can see 2(2n² + 2n) is   a multiple of 2 but 1 isnt  a multiple of 2

=>  2(2n² + 2n) + 1  is not a multiple of 2

=> (2n + 1)(n + 3) + (2n + 1)(n - 2) is not a multiple of 2

Step-by-step explanation:

3 0
2 years ago
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