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3 years ago

14

a store has a contest to guess the mass of 10,000 penuts. if a penut has a mas of about 0.45 gram, what would be a reasonable gu

ess for the mass of 10,000 peanuts

1 answer:

WITCHER [35]3 years ago

7 0

4,500 mass. if you multiply 0.45 and 10,000 you'll get 4,500

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The base of a trapezoid are 24 feet and 16 feet. The height of the trapezoid is 12 feet. what is the area of the trapezoid?

kobusy [5.1K]

Answer:

240 ft^2

Step-by-step explanation:

area: (24+16)12/2=240 ft^2

(the area of a trapezoid is the sum of the bases multiplied by the height over 2.)

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3 years ago

Find the surface area and no links

Oliga [24]

Answer:

184 m²

Step-by-step explanation:

Surface Area = 2(10*2) + 2(10*6) + 2(2*6)

Surface Area = 2(20 + 60 + 12)

Surface Area = 2(92)

Surface Area = 184 m²

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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2 years ago

Edger Anderson earns $300 A week plus a 15 percent commission only on sales he makes after his first $1000 In sales.if Mr.Anders

Mama L [17]

525 is what i got as my answer good luck

4 0

3 years ago

Read 2 more answers

A croissant shop produces two products: bear claws (B) and almond filled croissants (C). Each bear claw requires 6 oz of flour,

Kruka [31]

Answer:

letter A: B = 400; C = 1000; Max Z = $380

Step-by-step explanation:

bear claws (B) need 6 oz of flour (f), 1 oz of yeast (y), 2 ts of paste (p)

croissants (C) need 3 oz of flour (f), 1 oz of yeast (y), 4 ts of paste (p)

putting that information in equations, we have:

B = 6f + y + 2p

C = 3f + y + 4p

The total number of resources (R) are:

R = 6600f + 1400y + 4800p

Let's call M our total profit, "k1" the number of B produced and "k2" the number of C produced.

So, we can state that:

M = k1*0.2 + k2*0.3

The number of resources R2 will demand is calculated like this:

R2 = k1*B + k2*C = (6k1+3k2)f + (k1+k2)y + (2k1+4k2)p

using R2 and R, we can make some inequations:

6k1+3k2 <= 6600 -> 2k1+k2 <= 2200

k1+k2 <= 1400

2k1+4k2 <= 4800 -> k1+2k2 <= 2400

if we try to maximize k2 (as it worths more), we will have k1 = 0 and k2 = 1200 (limited by p), but looking at the resources R, we will still have resources to use (f and y). Looking at B and C expressions, we see that removing one C gives enough 'p' to make 2 B, which is a good trade (as 2B worths 0.4 cents, and 1C worths 0.3 cents). we have 200 'y' remaining, so doing this 200 times give us k1 = 400 and k2 = 1000, and the only resource remaining will be some of 'f'.

calculating the profit M, we have:

M = 400*0.2 + 1000*0.3 = 380$

the right answer is letter A.

3 0

3 years ago

Plz help I will do anything

Basile [38]

There's no need to get into an ethical morass over math homework.

111.

M is 20% less than N means

M is 100-20=80% of N

M=0.80 N

M/N = 0.8 = 4/5

Ratio: 4/5

112.

When we know <em>a, </em>the average, and <em>n, </em>how many numbers there are, we know the sum <em>s</em>, because <em>a=s/n </em>so <em>s=na.</em>

So the sum of our six numbers is 6(3.5)=21 so the sum of the seven numbers is 21+4.2=25.2 so the average is 25.2/7 = 3.6

Answer: 3.6

113.

|2p + 4 | < 3

At p=-2 the absolute value is zero. As p gets more negative the absolute value argument (inside part) gets negative and the absolute value gets bigger, more positive. Eventually the inside will be exactly -3, when

2p +4 = -3

2p = -7

p = -7/2 = -3 1/2

So p=-4 will make the inequality false, and p=-3 is the smallest integer that makes the inequality true.

Answer: -3

114.

The distance from the origin is given by the Pythagorean Theorem and this one is a 3/4/5 right triangle:

$d = \sqrt{(-.3)^2 + (-.4)^2}=.5$

Answer: .5 or 1/2

4 0

3 years ago