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3 years ago

5

write a division problem that can be used to find the number of vans needed to carry the tourists.Then solve

1 answer:

WITCHER [35]3 years ago

8 0

How many vans are there?

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A car traveling 65 mph leaves 25 ft skid mark. What is the ratio of the speed (mph) to the lenght of skid marks (ft) give you an

Pie

The answer is 13:5 I did this by dividing the numbers by a common factor

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3 years ago

What is the domain of the following parabola? (5 points)

tigry1 [53]

Answer:

Step-by-step explanation:

The domain of this quadratic is "all real numbers." The function is defined for all x.

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4 years ago

Which two integers does the value of √88 lie?

Marizza181 [45]

88=4*22=> sqrt88=2sqrt22
sqrt22 is approximately sqrt25=5
so 4 < sqrt22 < 5
8 < 2sqrt22 < 10
8 < sqrt88 < 10

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4 years ago

What is 6/87 of 45638???????

lapo4ka [179]

Answer:

3,147.44828

Step-by-step explanation:

$\frac{6}{87} \: of \: 45638 \\ \\ = \frac{6}{87} \times 45638 \\ \\ = 6 \times 524.574713 \\ \\ = 3,147.44828$

5 0

3 years ago

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

4 years ago