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iVinArrow [24]

3 years ago

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Mathematics

2 answers:

Nuetrik [128]3 years ago

3 0

a^5 and could u give me brainliest please

neonofarm [45]3 years ago

3 0

${a}^{2} \times {a}^{3} \\ = {a}^{2 + 3} \\ = {a}^{5}$

I think this is the answer. Your question isn't proper so I think it might be what you are trying to say

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What’s another way to write 2x + (-2x) + 4 + (-3) ?

vladimir1956 [14]

2x \\\\ snubs kn
Blaknblkhblhkhiviyg carrot

5 0

2 years ago

determine whether the lines intersect and if so find the point of intersection and the cosine of the angle of intersection x=4t+

Fittoniya [83]

Answer:

As the lines are not intersecting nor parallel, they must be skew.

Step-by-step explanation:

Question is incomplete, we consider the nearest match available online.

Parametric equations of two lines are:

L₁ : x=4t+2 , y = 3 , z =-t+1

L₂: x=2s+2 , y= 2s+5 , z = s+1

If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.

$4t+2=2s+2 ---(1)\\ \\3=2s+5---(2) \\\\-t+1=s+1---(3)$

If lines are intersecting then parametric coordinates must be equal for some value of t and s.

$From (3)\\-t=s\\From (2)\\\\s=\frac{3-5}{2}\\\\s=-1\\\implies t=1\\\\To\,\,check\,\, the \,\,values \,\,of \,\,s\,\, and \,\,t \,\,for\,\,intersection\,\,put \,\,them\,\, in\,\, (1)\\\\4(1)+2= 2(-1)+2\\ 6\ne0$

Hence the lines are not intersecting nor parallel, they must be skew.

6 0

3 years ago

Could someone please help me

mamaluj [8]

The second attachment I solved in your another question.You may refer to that.

Apply Pythagorean theorem

x²=10²-6²

x²=100-36
x²=64
x=8cm

4 0

2 years ago

Read 2 more answers

The third term of an arithmetic sequence is 14 and the 9th term is -1. Find the first four terms of the sequence.

Liula [17]

Answer:

The first four terms of the sequence are : 19, 16.5 , 14 , 11.5

Step-by-step explanation:

In the given sequence:

a(3) = 14, a(9) = -1

The general term of a sequence in Arithmetic Progression is:

a(n) = a + (n-1)d

a(3) = a + (3 -1) d = a + 2 d

and a(9) = a + (9- 1 ) d = a + 8 d

⇒ a + 2 d = 14 ......... (1)

and a + 8 d = -1 ........... (2)

Now, solving the given system of equation, we get:

From (1), a = 14 - 2 d

Put in (2), we get:

a + 8 d = -1 ⇒ 14 - 2 d + 8d = -1

⇒ 14 + 6d = -1

or, 6d = -1 -14 = -15

⇒ d = -15/6 = -2.5

or, d = -2.5

Then a = 14 - 2 d = 14 - 2(-2.5) =14 + 5 = 19, or a = 19

Now, first four terms of the sequence is:

a = 19

a(2) = a + 4 = 19 - 2.5 = 16.5

a(3) = a + 2d = 19 + 2(-2.5) = 19 - 5 = 14

a(4) = a + 3d = 19 + 3(-2.5) = 19 - 7.5 = 11.5

Hence, the first four terms of the sequence are : 19, 16.5 , 14 , 11.5

4 0

3 years ago

HELP!!! I don’t understand this question!

natka813 [3]

Answer:

Step-by-step explanation:

(2^6)^-5 is the expression that should be multiplied

7 0

3 years ago