<span><span><span><span><span><span>x</span><span>=</span><span>2</span><span>(</span><span>y</span><span>+</span><span>3</span><span>)</span></span></span></span></span></span><span>x=<span><span>9</span><span><span>2(y−37)</span></span><span></span>
</span></span><span><span>
</span></span>
A. Area = ½b × h
= ½ × 16 × 9
= 72
B. Area = b × h
= 26 × 18
= 468
C. Area = a²
= 11²
= 121
D. Area = ½(a+b) × h
= ½(6+21) × 8
= 108
Hope this helps :)
Please consider marking my answer the brainliest!
Since this is a 45-45-90 right triangle, the hypotenuse = sqrt2 * leg
24 is the hypotenuse so we need to find the leg.
24 = sqrt2 * leg
Divide both sides by sqrt2
leg = 16.97
A = (1/2)b*h
A = (1/2)*16.97*16.97
A = 144ft^2
What is it?
The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
How do you find IQR?
<em>Step 1: Put the numbers in order. ...</em>
<em>Step 2: Find the median. ...</em>
<em>Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...</em>
<em>Step 4: Find Q1 and Q3. ...</em>
<em>Step 5: Subtract Q1 from Q3 to find the interquartile range.</em>
Answer:
159.8195397043133
Step-by-step explanation:
2²⁰
------------------ = 159.8195397043133
3⁸
