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Natasha2012 [34]
3 years ago
9

Answer quickly please

Mathematics
2 answers:
Olin [163]3 years ago
7 0
Its a non-linear because it is a quadratic function
olga nikolaevna [1]3 years ago
3 0

Answer:

linear I think so ................

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a washer and a dryer cost 659$ combined. The washer costs 91$ less than the dryer, how much was the dryer?  
Darina [25.2K]
W+D=659

W=D-91

---------------------------

(D-91)+D=659

D-91+D=659

2D=750

D=750/2=375

------------------------------

W+375=659

W=284

------------------------------

So the dryer had cost $375 and the washer had cost $284.
7 0
3 years ago
Read 2 more answers
Can someone help. pls ​
Elan Coil [88]

Answer: 5

Step-by-step explanation:

Pythagorean Theorem = a^2 + b^2 = c^2 (hypotenuse)

the square root of 4^2 + 3^2 = c

c = 5

3 0
3 years ago
If the man has 20 dollars in his bank account and spends 2 dollars a day on coffee. How much money will he have in his account a
musickatia [10]
HEs going to have 14 dollars left
2x3=6
20-6=14
7 0
3 years ago
Please help me yall
allochka39001 [22]
The coordinates of D is (3,-1) i’m pretty sure if not i’m sorry.
3 0
3 years ago
Which statement describes whether a right triangle can be formed using one side length from each of these squares?
balu736 [363]

Answer:

Step-by-step explanation:

The area of the given squares are

Area = 64 in

Area = 225 in

Area = 289 in

The length of each side of a square is determined by finding the square root of its area. For the first square, the length of its side is √64 = 8inches. For the second square, the length of its side is √225 = 15inches. For the third square, the length of its side is √289 = 17inches.

For a right angle triangle to be formed, Pythagorean theorem must be obeyed. Sum of the square of the smaller sides must equal the square of the longer side. Therefore,

8² + 15² = 17²

289 = 289

Therefore, the correct statement is

Yes, a right triangle can be formed because the sum of the areas of the two smaller squares equals the area of the largest square

4 0
3 years ago
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