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Natasha2012 [34]
3 years ago
9

Answer quickly please

Mathematics
2 answers:
Olin [163]3 years ago
7 0
Its a non-linear because it is a quadratic function
olga nikolaevna [1]3 years ago
3 0

Answer:

linear I think so ................

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Find the solution to the equations.<br> 2х-у=-3<br> х+у=0<br><br> 0,0<br><br> -1,1<br><br> 1,-1
kobusy [5.1K]
It’s 0,0. The correct answer!
3 0
3 years ago
Read 2 more answers
Y=(x-4) ²-2<br> Find the vertex. How do you do that ?
AnnyKZ [126]
It’s a lot of steps but the answer is The minimum value -2 at X=4
7 0
3 years ago
Read 2 more answers
What goes outside during division with fractions? The numerator, or the denominator?
Ymorist [56]

Answer:

Denominator

Step-by-step explanation:

Think of it this way - numerator/denominator = nana/dog

Nana goes inside to the bathroom, but the dog goes outside to do its thing

If it was the other way around, it wouldn't be very pleasant.

LOL

Anyway, I hope this was helpful

Mark as Brainliest if it was

6 0
4 years ago
Altitudes $\overline{ax}$ and $\overline{by}$ of acute triangle $abc$ intersect at $h$. if $\angle ahb = 132^\circ$, then what i
Sergio [31]
Answer: 48 degrees

-------------------------------------------------------

See the attached image for a visual of the problem and answer.

Based on the diagram, we have angle AHB = 132 degrees (given) equal in measure to angle XHY since these two angles are vertical angles. 

Angles HYC and HXC are right angles due to the nature of AX and BY being altitudes. Recall that altitudes are segments that go from one vertex to the opposite side and they are perpendicular to the opposite side.

Focus on quadrilateral HXCY. So far, we know that...
Angle XHY = 132 degrees
Angle HYC = 90 degrees
Angle HXC = 90 degrees

The angle we want to find is angle ACB, which is the same as angle YCX. This angle is the missing angle of the quadrilateral HXCY.

For any quadrilateral, the four angles must add to 360 degrees. 

(angle XHY) + (angle HYC) + (angle HXC) + (angle YCX) = 360
(132) + (90) + (90) + (angle YCX) = 360
312 + (angle YCX) = 360
312 + (angle YCX) - 312 = 360 - 312
angle YCX = 48 degrees

Since angle ACB is the same as angle YCX, we can say
angle ACB = angle YCX = 48 degrees

So in summary,
angle ACB = 48 degrees

4 0
4 years ago
Can a triangle have sides with the given lengths 1ft,5ft,11ft
Scilla [17]
Let a,b and c is side of a triangle where:
a = 1
b = 5
c = 11

a^2 + b^2 = c^2. if the following statement is right, then triangle have these side.

1^2 + 5^2 = 11^2
1 + 25 = 121
26 != 121 ( != means not equal to)

Therefore, triangle can't have side length of 1, 5 and 11 ft.
3 0
3 years ago
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