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sattari [20]
2 years ago
9

If f(x) =69-15x then f(f^-1(x))

Mathematics
1 answer:
xenn [34]2 years ago
8 0

If f(x)=69-15x  then f(f^{-1}(x))=x

Given :

f(x)=69-15x\\

Lets find out f^{-1}(x). The steps to find out f inverse are

Replace f(x) by y

y=69-15x\\Interchange \; the \; variables\\x=69-15y\\solve \; for \; y\\x-69=-15y\\Divide \; by \; -15\\\frac{-x+69}{15} =y\\Replace \;y \;with \; f^{-1}\\f^{-1}=\frac{-x+69}{15}

Now we find f(f^{-1}(x))

Replace inverse function in the place of x in f(x)

f(f^{-1}(x))=f(\frac{-x+69}{15} )=69-15(\frac{-x+69}{15})=69-(-x+69)=69+x-69=x\\f(f^{-1}(x))=x

Learn more :

brainly.com/question/11242094

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Given: AB ≅ BC , m∠MOC = 135° OM − angle bisector of ∠AOB Prove: ∠ABO ≅ ∠CBO
Gennadij [26K]

Answer:

See explanation

Step-by-step explanation:

1. Angles AOM and MOC are supplementry angles. If m∠MOC = 135°, then

m∠AOM = 180° - 135° = 45°

2. OM − angle bisector of ∠AOB, then

m∠AOM = m∠MOB = 45°

3. Now

m∠BOC = m∠MOC - m∠MOB

m∠BOC = 135° - 45° = 90°

4. Since m∠BOC = 90°, BO is perpendicular to AC.

5. Consider isosceles triangle ABC (because AB ≅ BC). BO is the height drawn to the base, so it is an angle B bisector too, thus

∠ABO ≅ ∠CBO

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2 years ago
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3 years ago
PLZ HELP!!!! WILL GIVE BRAINLIEST ANSWER!!!
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What is the solution to the linear equation? 2/5 + p = 4/5 + 3/5p ​
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Step-by-step explanation:

2/5 + p = 4/5 + 3/5p

Multiply each side by 5 to clear the fractions

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2 +5p = 4 + 3p

Subtract 3p from each side

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