Answer:
See explanation
Step-by-step explanation:
1. Angles AOM and MOC are supplementry angles. If m∠MOC = 135°, then
m∠AOM = 180° - 135° = 45°
2. OM − angle bisector of ∠AOB, then
m∠AOM = m∠MOB = 45°
3. Now
m∠BOC = m∠MOC - m∠MOB
m∠BOC = 135° - 45° = 90°
4. Since m∠BOC = 90°, BO is perpendicular to AC.
5. Consider isosceles triangle ABC (because AB ≅ BC). BO is the height drawn to the base, so it is an angle B bisector too, thus
∠ABO ≅ ∠CBO
the correct answer is - 1/2
I think the answer is C-No solutions
Answer:
p=1
Step-by-step explanation:
2/5 + p = 4/5 + 3/5p
Multiply each side by 5 to clear the fractions
5(2/5 + p) = 5(4/5 + 3/5p)
2 +5p = 4 + 3p
Subtract 3p from each side
2+5p-3p = 4+3p-3p
2+2p = 4
Subtract 2 from each side
2+2p -2 = 4-2
2p =2
Divide by 2
2p/2 = 2/2
p=1