What is the vertex of the quadratic function f(x)=(x-8)(x-2)

1 answer:

7 0

F(x)=(x−8)(x−2)

y=(x−5)2−9
(Pretend the 2 is an exponent)

Use the vertex form, y=a(x−h)2+ky=a(x-2+k, to determine the values of a,h, and k.

a=1
h=5
k=-9

Find the vertex (h, k).
(5, -9)

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Let's call their parts w,m and s

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area = 25.5 cm²

Step-by-step explanation:

i have shown in the image you have to rotate it to see how i worked the area out

i am very sorry i cant work the perimeter out since i have no idea what the length of the two sides of the triangle are . if you need help on understanding how i worked out the area please let me know .

hopefully i was able to help you in half of the question i am sorry for not helping on the perimeter :)