0.02 can go into 84, 4200 times. Your answer is <u>incorrect</u>, the <u>correct answer</u> is 4200.
Answer:
90.80
Step-by-step explanation:
6x+4
= (6)(13)+4
= 78+4
=82
3x
=(3)(13)
= 39
So we know the sides are 39 and 82
Pythagoras theorem in triangles
= a2+b2= c2
Now, we know the value of a and B but not c (the hypotenuse)
Therefore,
c2 = (39)^2 + (82)^2
= 1521+ 6724
= 8245
so, c = √8245
= 90.80 unitd
X^2 - 10x + 8 =0
x^2 - 10 + (-10/2)^2 - (-10/2)^2 + 8 = 0
(x - 5)^2 - 25 + 8 = 0
(x - 5)^2 - 17 = 0
To be honest , this is the final step for this equation. It seems like there is no any suitable answer for this question..
To me , I think the best answer will be the third option.
x - 5 =0
x = 5
2x-10 = 0
2x = 10
x = 5
I guess this answer seems like legit.. So I will choose the third option.
<span> first, write the equation of the parabola in the required form: </span>
<span>(y - k) = a·(x - h)² </span>
<span>Here, (h, k) is given as (-1, -16). </span>
<span>So you have: </span>
<span>(y + 16) = a · (x + 1)² </span>
<span>Unfortunately, a is not given. However, you do know one additional point on the parabola: (0, -15): </span>
<span>-15 + 16 = a· (0 + 1)² </span>
<span>.·. a = 1 </span>
<span>.·. the equation of the parabola in vertex form is </span>
<span>y + 16 = (x + 1)² </span>
<span>The x-intercepts are the values of x that make y = 0. So, let y = 0: </span>
<span>0 + 16 = (x + 1)² </span>
<span>16 = (x + 1)² </span>
<span>We are trying to solve for x, so take the square root of both sides - but be CAREFUL! </span>
<span>± 4 = x + 1 ...... remember both the positive and negative roots of 16...... </span>
<span>Solving for x: </span>
<span>x = -1 + 4, x = -1 - 4 </span>
<span>x = 3, x = -5. </span>
<span>Or, if you prefer, (3, 0), (-5, 0). </span>
So you have to find something that multiples to six but also somehow either subtracts or adds to five. So I would pick 2 and 3 because two plus three is five. Then you would write out your equation
X2+2x+5x+6
This may not be the way your teacher taught however it is much easier for me to do it this way.
