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Hoochie [10]
2 years ago
13

Solve x+2=10

Mathematics
1 answer:
Anna71 [15]2 years ago
8 0
X = 8

Just subtract 10 - 2 and you’ll get 8
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Can someone help please?
deff fn [24]
Slope = 75
Y-intercept = 150
8 0
3 years ago
Jarvis invested some money at 6% interest. Jarvis also invested $58 more than 3 times that amount at 9%. How much is invested at
DerKrebs [107]

9514 1404 393

Answer:

  • $3309 at 6%
  • $9985 at 9%

Step-by-step explanation:

Let x and y represent amounts invested at 6% and 9%, respectively.

  y = 3x +58 . . . . . . . the amount invested at 9%

  0.06x +0.09y = 1097.19 . . . . . . total interest earned

__

Substituting for y, we have ...

  0.06x +0.09(3x +58) = 1097.19

  0.33x + 5.22 = 1097.19 . . . . . . . . . simplify

  0.33x = 1091.97 . . . . . . . . . . . . subtract 5.22

  x = 3309 . . . . . . . . . . . . . . . . divide by 0.33

  y = 3(3309) +58 = 9985

$3309 is invested at 6%; $9985 is invested at 9%.

8 0
3 years ago
Failed his first test, what is the probability that steve will fail his next drug test
CaHeK987 [17]
If he failed it once, then the probability out of two times is 1/2. He has a 50% chance of failing the drug test again.

I hope this helps!
4 0
3 years ago
PLSS HELP ME WITH THIS! 15 POINTS!
irina [24]

Answer:

2w - 13

Step-by-step explanation:

here we just simplify the expression,

3w - 4 - w - 9

becomes:

2w - 13

5 0
2 years ago
Read 2 more answers
Suppose we want to choose 5 objects, without replacement, from 15 distinct objects.
goblinko [34]

15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.

Given that, suppose we want to choose 5 objects, without replacement, from 15 distinct objects.

<h3>What is a permutation?</h3>

A permutation is a mathematical calculation of the number of ways a particular set can be arranged, where the order of the arrangement matters.

Now, 13P_{5}= 13!/(13-5)!

= 13!/8! = 13x12x11x10x9= 1287 x 120 = 15,444

Therefore, 15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.

To learn more about the permutation visit:

brainly.com/question/1216161.

#SPJ1

3 0
2 years ago
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