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Ainat [17]
3 years ago
9

Help Me With These Please

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0
10×sine of 60 degrees=8.66 which is the same as B. you can check by finding the square root of 3 and then multiplying that by 5.
You might be interested in
Question: A square with sides of length 5 is positioned inside a square with sides of length 7. What is the total area between t
Sergio [31]

Answer:

The total area between the squares is of 24 units squared.

Step-by-step explanation:

Area of a square:

The area of a square of side length l is given by:

A = l^2

Area between figures:

The area between two figures is the area of the larger figure subtracted by the area of the smaller figure.

Larger square:

Square with side of length 7. So

A_l = 7^2 = 49

Smaller square:

Square with side of length 5. So

A_s = 5^2 = 25

What is the total area between the squares? ​

T = A_l - A_s = 49 - 25 = 24

The total area between the squares is of 24 units squared.

6 0
2 years ago
A company uses two vans to transportworkers from a free parking lot to theworkplace between 7:00 and 9:00 a.m.One van has 6 more
OverLord2011 [107]
X = small van capacity, y = larger van capacity
y = x + 6

2x + y = 57
now we sub in x + 6 for y
2x + x + 6 = 57
3x + 6 = 57
3x = 57 - 6
3x = 51
x = 51/3
x = 17

y = x + 6
y = 17 + 6
y = 23

small van (x) has 17 seats and large van (y) has 23 seats

3 0
3 years ago
Reduce -7/8 + (-1/2) to the simplest form.
ololo11 [35]

Answer:

-1.375

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Michela says that the modes of the two data are the same so the median and mean must also be the same. what is michela’s error?
aev [14]

Answer: median and mean are the same

Step-by-step explanation:

The error committed by Michela is by saying

The median and mean are the same.

Because in statistics, we can't use mode to predict the median and the mean.

7 0
3 years ago
An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
2 years ago
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