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chubhunter [2.5K]
2 years ago
9

A pet store has two tanks of tropical fish. The first tank contains 2 blue fish and 7 yellow fish and the second tank contains 6

blue fish and 3 yellow fish. If Keisha randomly purchases a fish from each tank, what is the probability that both fish will be blue?
A. 4/9
B. 8/81
C. 4/27
D. 1/12
Mathematics
1 answer:
makkiz [27]2 years ago
4 0

Answer:

the answer is a

Step-by-step explanation:

add the total of all fish together and put the number of blue fish on top of that to get 8/18 and simplify to get 4/9

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Use the net to find the approximate surface area of the cylinder to the nearest square meter.
lyudmila [28]

Answer: D

Step-by-step explanation:

Formula= 2piRh +2piR^2

2pi*7*11 + 2pi*49 = 791.68 or 792

4 0
3 years ago
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10. The sides of a number cube have the numbers 9, 3, 5, 3, 7, and 9. If the
ddd [48]

Answer:

1/3 or 33.333333333%

Step-by-step explanation:

Two 9's

Six number possible

2/6= 1/3

Probability:

1/3 or 33.33333333%

3 0
2 years ago
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One of your friends is testing the effect of drinking coffee on the duration of cold symptoms. The common cold lasts, on average
Nonamiya [84]

Answer:

0.0930

Step-by-step explanation:

Given that one of your friends is testing the effect of drinking coffee on the duration of cold symptoms. The common cold lasts, on average, 6 days.

she tests a one-sided alternative about the population mean cold duration when drinking coffee, H0: μcoffee = 6 Ha: μcoffee < 6 She finds z = −1.68 with one-sided P-value P = 0.0465.

If hypotheses changed to two tailed as:

H_0: \mu_{coffee}  = \mu_{tea}\\H_a: \mu_{coffee}\neq \mu_{tea}

(Two tailed test)

Since we have mean difference and std error the same, test statistic would remain the same.

p value for two tailed would be = twice the p value for one tail

=2(0.0465)\\= 0.0930

6 0
3 years ago
Convert 3 4/7 into an improper fraction.
Marizza181 [45]
25/7
You multiply 3 and 7 which gives you 21. Add 4 to 21, giving you 25. The improper fraction would be 25/7
7 0
2 years ago
Drag each tile to the correct box.
Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

f(a)=h(3)=4  

f(b)=h(5)=16

a=3

b=5

Substitute

\frac{16-4}{5-3}=6

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

f(a)=f(3)=10  

f(b)=f(6)=35

a=3

b=6

Substitute

\frac{35-10}{6-3}=8.33

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

g(x)=\frac{1}{5}(4)^x

f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}  

f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}

a=2

b=3

Substitute

\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0
3 years ago
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