2 years ago

Find E, the midpoint of RD, if R(4, –5) and D(2, 3).

Mathematics

1 answer:

dedylja [7]2 years ago

8 0

Answer:

E (3;-1)

Step-by-step explanation:

the 'x' coordinate of E: (4+2)/2=3;

the 'y' coordinate of E: (-5+3)/2= -1.

You might be interested in

Solve the problem. 9/13 divided by 4/5 =

Dominik [7]

54/52 is the answer or you could reduce it to 27/26

5 0

3 years ago

Read 2 more answers

- 7th Grade Work -<br><br> Please help, and answer only if you have an answer for this problem.

Serggg [28]

Answer:

8.5

Step-by-step explanation:

120 * 0.4 = 48 + 20 = 68

120 * 0.45 = 54 + 22.25 = 76.5

76.5 - 68 = 8.5

8 0

2 years ago

Read 2 more answers

(x^3 -6x^2 -7x -9)/ (x-3)

maks197457 [2]

The answer is x^2 - 3x - 8 - (33/(x - 3))

7 0

3 years ago

2. A store sells an assortment of batteries

astra-53 [7]

Answer:

30%

Step-by-step explanation:

# of bulk packs = 300

# of triple As = 90

% = 90 / 300 * 100%

% = .3 * 100%

% = 30%

3 0

3 years ago

Read 2 more answers

What is (f ° g)(2) and (g ° f)(2) with the set of points f: {(0,4), (1,2), (2,0), (3,2), (4,4)} and g: {(0,4), (1,3), (2,2), (3,

kumpel [21]

Answer:

$\large\boxed{(f\circ g)(2)=0}\\\boxed{(g\circ f)(2)=4}$

Step-by-step explanation:

$f:\{(0,4), (1,2), \underline{(2,0)}, (3,2), (4,4)\}\\\\g:\{\underline{(0,4)}, (1,3), \underline{(2,2)}, (3,1), (4,0)\}\\\\(f\circ g)(x)=f\bigg(g(x)\bigg)\\\\g(2)=2\qquad/from\ (2,2)/\\f\bigg(g(2)\bigg)=f(2)=0\qquad/from\ (2,0)/\\\\(g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(2)=0\qquad/from\ (2,0)/\\g\bigg(f(2)\bigg)=g(0)=4\qquad/from\ (0,4)/$

7 0

2 years ago