All categories

3 years ago

Pls i need this, it’s due today. i will mark brainliest.

Mathematics

1 answer:

MArishka [77]3 years ago

8 0

Answer:

Step-by-step explanation:

Y intercepts : 5,-1,3,7,1

X- intercepts: 2,3,1,-1

Its decreasing

It is a negative slope

Maximum : 7 for y

Min : -1

You might be interested in

The market is located at point (−4, −3) on the coordinate graph. The barber shop is 8 units to the right and 4 units up from the

Evgesh-ka [11]

Answer:

(4, 1)

Step-by-step explanation:

8 units to the right = x + 8, so -4 + 8 = 4

4 units up = y + 4, so -3 + 4 = 1

4 0

3 years ago

3+-√(-3)^2 - 4(5)(-1)

Alona [7]

Answer:

Step-by-step explanation:

Easy way to do this is step by step. Your quadratic, from your entry, must be

$5x^2-3x-1$ .

Step by step looks like this, one thing at a time:

$x=\frac{3+\sqrt{(-3)^2-4(5)(-1)} }{2(5)}$ becomes

$x=\frac{3+\sqrt{9-(-20)} }{10}$ becomes

$x=\frac{3+\sqrt{9+20} }{10}$

and this of course is

$x=\frac{3+\sqrt{29} }{10}$

Do the same with the subtraction sign to get the other solution.

If you're unsure of how to enter it into your calculator, do it step by step so you don't mess up the sign. If you enter it incorrectly, you could end up with an imaginary number when it should be real, or a real one that should be imaginary.

Just my advice as a high school math teacher.

3 0

3 years ago

Help please I’ll mark brainliest

aleksklad [387]

Answer:

12 miles

Step-by-step explanation:

4*3 =12

7 0

3 years ago

Find the slope of the line. Write your answer in simplest form.

Savatey [412]

The slope of this line is: m = 3/4

3 0

3 years ago

Hi! I was wondering if you could help with this question please :)

Makovka662 [10]

Answer:

$R=\frac{QJ}{I^2t}$

Step-by-step explanation:

So we have the equation:

$Q=\frac{I^2Rt}{J}$

And we want to solve for R.

First, let's multiply both sides by J to remove the fraction on the right. So:

$(J)Q=(J)\frac{I^2Rt}{J}$

Simplify the right:

$JQ=I^2Rt$

We can rewrite our equation as:

$JQ=R(I^2t)$

So, to isolate the R variable, divide both sides by I²t:

$\frac{JQ}{I^2t}=\frac{R(I^2t)}{I^2t}$

The right side cancels, so:

$R=\frac{QJ}{I^2t}$

And we are done!

7 0

3 years ago