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Gnoma [55]
3 years ago
13

1. In order to write a biconditional, the conditional and its

Mathematics
1 answer:
Elza [17]3 years ago
4 0

Answer:

C

Step-by-step explanation:

It was just in my notes....

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Find the future value of a simple interest loan of $29,500 at 9.5% interest for 10 months
goblinko [34]

Answer:

$2335.62

Step-by-step explanation:

I=PTR/100

I=29500×9.5×10/100×12

$2335.62

8 0
3 years ago
Solve the equation for the indicated variable.<br> А= 1/2bh for b
Eduardwww [97]
A = 1/2bh

Divide h by both sides.

A/h = 1/2b

Divide 1/2 by both sides.

b = 2a/h

4 0
3 years ago
Find the value of<br> a if 3x+ay=6​
Akimi4 [234]
I guess =ay=6-3x= ay/y=6-3x/y= a=6-3x/y
6 0
3 years ago
Read 2 more answers
13. Write
Bingel [31]

First off, we factor out the expression:

\displaystyle \large{y = 2 {x}^{2}  - 12x + 16} \\  \displaystyle \large{y = 2 ( {x}^{2} - 6x + 8) }

In the bracket, separate 8 out of the expression.

\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 8)] }\\  \displaystyle \large{y = 2[ ( {x}^{2} - 6x) + 8]}

In x^2-6x, find the third term that can make up or convert it to a perfect square form. The third term is 9 because:

\displaystyle \large{ {(x - 3)}^{2}  =  {x}^{2}  - 6x + 9}

So we add +9 in x^2-6x.

\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 9)  + 8]}

Convert the expression in the small bracket to perfect square.

\displaystyle \large{y = 2[  {(x - 3)}^{2}   + 8]}

Since we add +9 in the small bracket, we have to subtract 8 with 9 as well.

\displaystyle \large{y = 2[  {(x - 3)}^{2}   + 8 - 9]} \\  \displaystyle \large{y = 2[  {(x - 3)}^{2}   - 1]}

Then we distribute 2 in.

\displaystyle \large{y = 2[  {(x - 3)}^{2}   - 1]} \\

\displaystyle \large{y = 2[  {(x - 3)}^{2}   - 1]} \\ \displaystyle \large{y = [2 \times  {(x - 3)}^{2} ]+[ 2 \times ( - 1)] } \\ \displaystyle \large{y = 2 {(x - 3)}^{2}  - 2 }

Remember that negative multiply positive = negative.

Hence the vertex form is y = 2(x-3)^2-2 or first choice.

4 0
3 years ago
sandy is upgrading her internet service fast charges $60 for installation and $50.45 per month quick internet has free installat
seraphim [82]
Answer:
60+50.45x=57.95x

Cost of Fast Internet:
$60 for installation and $50.45 per month for months =

Cost of Quick Internet:
Free installation and $57.95 per month for months =

We want to know in how many months BOTH COSTS WOULD BE SAME. So we EQUATE the expressions for both. We have:

This equation can be solved for x to find the number of months for which the internet service would cost the same.

Read more on Brainly.com - brainly.com/question/893458#readmore
4 0
3 years ago
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