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Phantasy [73]
2 years ago
9

Use substitution method 3x +4y+175x-2y=11​

Mathematics
1 answer:
Viefleur [7K]2 years ago
4 0

3x +4y+175x-2y=11

4y-2y+175x+3x=11

2y+178x=11

2y=11-178x

y=\frac{11-178x}{2}

y=-89x+\frac{11}{2}

178x=-2y+11

x=\frac{-2y+11}{178}

x=\frac{-1}{89} y+\frac{11}{178}

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What is 10n+2=7n+14
Orlov [11]

Answer:

n = 4

Step-by-step explanation:

Given

10n + 2 = 7n + 14

Collect terms in n on the left side and numbers on the right side

Subtract 7n from both sides

3n + 2 = 14 ( subtract 2 from both sides )

3n = 12 ( divide both sides by 3 )

n = 4

4 0
3 years ago
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Which figures will have a volume that is greater than 100 cubic units? Select two options.
igor_vitrenko [27]

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B and D

Step-by-step explanation:

5 0
1 year ago
34​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 student are sampled, so n = 10

34% of college students say they use credit cards because of the rewards program, so \pi = 0.34

(a) exactly​ two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157

P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573

P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320

P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0
3 years ago
What are the coordinates of the roots of the equation x sqaured + 4x + 3= 0
scZoUnD [109]

Answer:

a

x

2

+

b

x

+

c

=

0

the formula for the roots is

x

=

−

b

±

√

b

2

−

4

a

c

2

a

(

1

)

Identify the values for

a

,

b

,

&

c

x

2

+

4

x

+

3

=

0

cmp

a

x

2

+

b

x

+

c

=

0

a

=

1

b

=

4

c

=

3

(

2

)

Substitute these numbers into eh formula

x

=

−

4

±

√

4

2

−

(

4

×

1

×

3

)

2

×

1

(

3

)

Carefully proceed and do the calculations

x

=

−

4

±

√

16

−

12

2

x

=

−

4

±

√

4

2

x

=

−

4

±

2

2

now calculate the two separate solutions

x

1

=

−

4

+

2

2

=

−

2

2

=

−

1

x

2

=

−

4

−

2

2

=

−

6

2

=

−

3

Answer link

Step-by-step explanation:

8 0
2 years ago
How to factor 1-49c^2
Dima020 [189]
Ok so this is a difference of 2 perfect squares
1=1^2
49c^2=(7c)^2
to factor you remember
a^2-b^2=(a+b)(a-b) so

1^2-(7c)^2=(1+7c)(1-7c)
5 0
3 years ago
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