Write out the problem. ...Simplify the first fraction. ...Simplify the second fraction. ...Multiply the numerators of both fractions. ...Multiply the denominators of both fractions. ...Place the new numerator over the new denominator.
Given:
m∠B = 44°
Let's find the following measures:
m∠A, m∠BCD, m∠CDE
We have:
• m∠A:
Angle A and Angle B are interior angles on same side of a transversal.
The interior angles are supplementary.
Supplementary angles sum up to 180 degrees
Therefore, we have:
m∠A + m∠B = 180
m∠A + 44 = 180
Subtract 44 from both sides:
m∠A + 44 - 44 = 180 - 44
m∠A = 136°
• m,∠,BCD:
m∠BCD = m∠A
Thus, we have:
m∠BCD = 136°
• m∠CDE:
Angle C and angle CDE form a linear pair.
Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.
Thus, we have:
m∠D = m∠B
m∠D = 44°
m∠CDE + m∠D = 180
m∠CDE + 44 = 180
Subract 44 from both sides:
m∠CDE + 44 - 44 = 180 - 44
m∠CDE = 136°
ANSWER:
• m∠A = 136°
,
•
,
• m∠BCD = 136°
,
•
,
• m∠CDE = 136°
X=6y
sum of their reciprocals
(1/x)+(1/y)=7
x=6y
1/6y+1/y=7
1/6y+6/6y=7
7/6y=7
times both sides by 6y
7=42y
divide both sides by 42
1/6=y
x=6y
x=6(1/6)
x=6/6
x=1
the numbers are 1 and 1/6
Answer:
No answer can be found
Step-by-step explanation:
There isn't any value to find and express in simplest form lol.
Answer:
Vase volume is 452.16 in³
Step-by-step explanation:
The question asks for the volume of a cylinder of radius r and height h. The relevant formula is V = (pi)(r)^2*h
With h = 9 in and r = 4 in, that max volume (of water) is
V = (3.14)(4 in)^2*(9 in) = 452.`16 in³
