The Slope of "<span>2x - 3y - 5 = 0" is:
m = 2/3.
Use the mx+y formula to solve this question.
The correct answer is: B
This is a verified answer. </span>
Because of the symmetry, we can just go from x=0 to x=2 to find the area between
<span>y = x^2 and y = 4 </span>
<span>that area = ∫4-x^2 dx from 0 to 2 </span>
<span>= [4x - (1/3)x^3] from 0 to 2 </span>
<span>= 8 - 8/3 - 0 </span>
<span>= 16/3 </span>
<span>so when y = b </span>
<span>x= √b </span>
<span>and we have the area as </span>
<span>∫(b - x^2) dx from 0 to √b </span>
<span>= [b x - (1/3)x^3] from 0 to √b </span>
<span>= b√b - (1/3)b√b - 0 </span>
<span>(2/3)b√b = 8/3 </span>
<span>b√b =4 </span>
<span>square both sides </span>
<span>b^3 = 16 </span>
<span>b = 16^(1/3) = 2 cuberoot(2) </span>
<span>or appr 2.52</span>
The first step to solve this problem is to find the area of
the rectangular piece of fabric.
A of triangle = bh/2
A = (14 cm) (6 cm) /2
A = 84 cm^2 / 2
A = 42 cm
And since there are 31 pieces of the fabric, the total area
of all the pieces of fabric is:
31 pieces of fabric x 42 square centimeters per piece =
1,302 square centimeters
To computer how many congruent triangular patches can be
cut, you have to divide the total area of the fabric pieces with the area of
the congruent triangle:
1,302 square centimeters / 21 square centimeters = 62
Therefore, Leia can cut 62 patches.
Answer:
the answer is inverse operations
Given Information:
number of trials = n = 1042
Probability of success = p = 0.80
Required Information:
Maximum usual value = μ + 2σ = ?
Minimum usual value = μ - 2σ = ?
Answer:
Maximum usual value = 859.51
Minimum usual value = 807.78
Step-by-step explanation:
In a binomial distribution, the mean μ is given by
μ = np
μ = 1042*0.80
μ = 833.6
The standard deviation is given by
σ = √np(1 - p)
σ = √1042*0.80(1 - 0.80)
σ = √833.6(0.20)
σ = 12.91
The Maximum and Minimum usual values are
μ + 2σ = 833.6 + 2*12.91
μ + 2σ = 833.6 + 25.82
μ + 2σ = 859.51
μ - 2σ = 833.6 - 25.82
μ - 2σ = 807.78
Therefore, the minimum usual value is 807.78 and maximum usual value is 859.51
