You have to move the -2/5 by the 11j to get k by its self
K=11j+-2/5
300 miles is equal to 528,000 yards
Answer:
about 2.81 km/h
Step-by-step explanation:
It can be useful to draw a diagram.
The lines pointing to due north from points B and P are parallel, so the angle BCP and the bearing of point C from P are the same, 30°. The angle BPC will be the difference of bearings of B and C at P, so is 47-30=17°. This is enough information to solve the triangle using the Law of Sines:
PB/sin(C) = CB/sin(P)
CB = PB·sin(P)/sin(C) = (1200 m)·sin(17°)/sin(30°) ≈ 701.7 m
The speed of the boat is then ...
x = distance/time = (0.7017 km)/(1/4 h) = 2.8068 km/h
1 mile = 5280 feet, so we multiply 6.25 by 5280 to get 33000 feet. 1 yard = 3 feet, so we divide 3 by 33000 to get 11000 yards.
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Hope this helps!
==jding713==