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Karolina [17]
3 years ago
9

A=8, b=?, c=16 find the missing side

Mathematics
1 answer:
Ksivusya [100]3 years ago
4 0

Answer:

13.8 I think

Step-by-step explanation:

using the pyrhagorem theorem use the formula c=a2+b2

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Write the following phrase as a variable expression. Use X to represent “a number.” The sum of eleven, a number, and the product
melamori03 [73]

Answer:

11 + x + 19*x

Step-by-step explanation:

The sum of eleven, a number, and the product of nineteen and the number.

we have to read carefully and understand how to interpret

when he says the sum of separates into 3 parts because there is a "comma" and an "and"

Now let's separate the 3 parts of the sum

1 part

says eleven so we just put 11

eleven = 11

2 part

in the text it says that we replace "a number" with x

a number = x

3 part

In this case we simply make the product between the given values

the product of nineteen and the number

19 * x

Now we can accommodate everything and we finish

11 + x + 19*x

6 0
3 years ago
Help me i need help ok try to explain and ok ok ok ok ok ok ok ok
Kaylis [27]

Question 9

18, 28, 6, 54

Question 10

Correct Number: 5

Incorrect Number: 6

7 0
3 years ago
Math work pls help :)​
PilotLPTM [1.2K]

Answer:

b. side angle side. hope this helps

8 0
3 years ago
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
What is 1/2 times seven
GREYUIT [131]
3.5 is your answer. :)



3 0
4 years ago
Read 2 more answers
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