Answer:
sin 105 = sin (45 + 60) = sin 45 cos 60 + cos 45 sin 60, or
= (1 / √2)(1 / 2) + (1 / √2)(√3 / 2)
1 + √3
= -------------
2√2
Step-by-step explanation:
<h2>
Answer:</h2>
The ratio of the area of region R to the area of region S is:
<h2>
Step-by-step explanation:</h2>
The sides of R are in the ratio : 2:3
Let the length of R be: 2x
and the width of R be: 3x
i.e. The perimeter of R is given by:
( Since, the perimeter of a rectangle with length L and breadth or width B is given by:
)
Hence, we get:
i.e.
Also, let " s " denote the side of the square region.
We know that the perimeter of a square with side " s " is given by:
Now, it is given that:
The perimeters of square region S and rectangular region R are equal.
i.e.
Now, we know that the area of a square is given by:
and
Hence, we get:
and
i.e.
Hence,
Ratio of the area of region R to the area of region S is:
Answer:
Pertaining to the yielded interrogate, the retort is 6.30.
Step-by-step explanation:
As disseminated, the terms may equate to the proximate as identified:
-If an inch is equivalent to the numeral equivalence of 2.54, hence 5 inches (in) is in the accordance with the equivalence to 12.7 centimeters (cm).
Alas, the terms may equate as the following:
19 cm - 12.7 cm = x
Thus, as to resolute and evaluate the retort, with respect to your interrogate, is 6.30.
*Hope this helps.
Answer:
Aziza’s claim is incomplete. The third side must be between 4 in. and 26 in.
Step-by-step explanation:
With the Triangle Inequality Theorem, saying that the sum of lengths of any two sides of a triangle is greater than the length of the third side. With this we can develop two inequalities:
11 + 15 > x
26 > x
rewrite this as x < 26
11 + x > 15
x > 15 - 11 Subtract 11 from both sides
x > 4
Therefore, the third side can be anywhere greater than 4 inches and less than and less than 26 inches.
4 < x < 26
For this problem, you would replace x with 7 then solve.
3/ (7+2) - sqrt(7-3) =
3/9 - sqrt(4) =
1/3 - 2 = -1 2/3 = -1.67
f(7) = 1
