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3 years ago

Jim has 2 pencils, 2 pens and 2 markers. Find the number of ways of choosing a pencil, a pen and a marker.

Mathematics

1 answer:

krok68 [10]3 years ago

3 0

Answer:

He can choose between 2 for the first, 2 for the second and 2 for the third. Every choice does not influence anything.

Step-by-step explanation:

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What is the equation of the line that passes through the point (-6,-8)(−6,−8) and has a slope of 1/3

Dmitriy789 [7]

Answer:

y= $\frac{1}{3}$ x-6

Step-by-step explanation:

because slope is 1/3

so y= $\frac{1}{3}$ x+b

plug in (-6,-8)

y= $\frac{1}{3}$ x-6

8 0

3 years ago

Read 2 more answers

Which of the following are exterior angles check all that apply?

yanalaym [24]

The exterior angles on this diagram are angle 4 and angle 2.

We can see this because an exterior angle is the angle that forms a straight line with an interior angle, so that 180 - [interior angle] = [exterior angle].

Therefore, angles 4 and 2 are the only angles that form straight lines with interior angles, so they are thus the exterior angles.

I hope this helps!

7 0

3 years ago

How would you break down 40% to find 40% of a number<br>

Alika [10]

Answer:

find 80 percent

Step-by-step explanation:

8 0

3 years ago

Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217

Soloha48 [4]

Answer:

$f(216) \approx 6.0093$

Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

Linear approximated as:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

$f(x) = \sqrt[3]{216}$

$f(x) = 6$

So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

$f(215 + 1) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

$f(x) = x^\frac{1}{3}$

Differentiate

$f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}$

Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

$f'(216) = \frac{6}{648}$

$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

$f(216) \approx 6 + 0.0093$

$f(216) \approx 6.0093$

6 0

3 years ago

What is the answer please help

german

What do you need help with? it helps us to know the question!

7 0

3 years ago