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2 years ago

Jim has 2 pencils, 2 pens and 2 markers. Find the number of ways of choosing a pencil, a pen and a marker.

Mathematics

1 answer:

krok68 [10]2 years ago

3 0

Answer:

He can choose between 2 for the first, 2 for the second and 2 for the third. Every choice does not influence anything.

Step-by-step explanation:

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One number is 3 less than a second number. Twice the second number is 14 more than 3 times the first. Find the two numbers

Butoxors [25]

Answer:

Number 1 is 10 and number 2 is 7

14/2 = 7

7 + 3 = 10

8 0

3 years ago

A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a

Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\$

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)$ [as x+y=14]

$\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\$

$\Rightarrow x =(25 \times 14)/32=10.9375$ grams

and $y = 14-x= 14-10.9375=3.0625$ grams.

Hence, 10.9375 grams of 82% gold and 3.0625 grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\$

$\Rightarrow x =(50 \times 14)/57=12.28$ grams

and $y = 14-x= 14-12.28=1.72$ grams.

Hence, 12.28 grams of 82% gold and 1.72 grams of 50% gold added to make 14 grams of 75% gold.

3 0

2 years ago

Which statements are true for the given quadrilaterals? Choose all answers that are correct. A. All trapezoids are quadrilateral

svetlana [45]

Trapezoids always have 4 sides, so this is true. All rhombuses have parallel sides, so B is true also. A trapezoid has two sides that are not parallel, so C is not true. (remember, you only have to find one instance where your statement is false for it to be false) And for D, all rhombuses are kite-shaped so D is not true. A and B are true. Hope this helps. :)

8 0

3 years ago

Read 2 more answers

PLEASE HURRY

faust18 [17]

Step-by-step explanation:

width= w

length = l=w+5

Area = l * w

104 =(w+5) * w

w2 +5w -104 =0

(w+13)(w-8)=0

w=13 and w=8

so width =8

length=13

3 0

2 years ago

Algebra problem below.

umka21 [38]

$A= \frac{1}{2}bh= \frac{1}{2}*18*11=9*11=99 \ ft^2$

3 0

3 years ago