Answer:
y=x+5
Step-by-step explanation:
So first you need to plug everything into the point-slope formula which is
y-y1=m(x-x1)
m being the slope and y1 and x1 being the point (5,10)
So once you plug it in it should look like this: y-10=1(x-5)
Now you solve it
First you need to distribute 1 in 1(x-5) which is (x-5)
Now you have y-10=x-5
Then you add 10 to both sides which is y=x+5
Your answer is y=x+5
Answer:
The product 
Step-by-step explanation:
Given expression
and 
We have to find the product of 
Consider the given expression 
Multiply fractions, we have,


Cancel common factor ( b - 5 )
we have, 
Apply exponent rule,




Cancel common factor b , we have,

Thus, the product 
Ik this is not what you were looking for but what kind of problem is this lol. i never seen this
This can be done easily if you choose a different probability.
Find the chance that none of the 5 graduates find a job.
For one student that is 100%-62%=38%
This has to happen for all 5 students, that is P=(0,38)^5=0,008 (rounded)
This is the chance that none of the 5 students finds a job. All of the above cases at least one finds a job.
That is 1-0,008=0,992 (rounded)