Step-by-step explanation:
a. lim(x→2) [g(x) + h(x)]
Use additive property of limits.
= lim(x→2) g(x) + lim(x→2) h(x)
= 0 + 5
= 5
b. lim(x→2) [3 h(x)]
Use multiplication property of limits.
= [lim(x→2) 3] [lim(x→2) h(x)]
= 3 lim(x→2) h(x)
= 3 (5)
= 15
c. lim(x→2) [g(x) h(x)]
Use multiplication property of limits.
= [lim(x→2) g(x)] [lim(x→2) h(x)]
= (0) (5)
= 0
Let x represent the cost per gallon of gasoline.
Let y or f(x) represent the cost of x gallons of gasoline.
Given that the cost per gallon is $2.79,
The function would be
f(x) = 2.79x
The domain refers to all possible values of x that can fit into the function. Given that the truck holds a maximum of 28 gallons, the maximum value of x is 28. When the truck is empty, the minimum value of x is 0. Therefore, the domain is 0 to 28
The range refers to all possibel values of y or f(x) that can satisfy the function.
When x = 0, f(x) = 2.79 * 0 = 0
When x = 28, f(x) = 2.79 * 28 = 78.12
The range would be 0 to 78.12
Domain: 0 to 28
Range: 0 t0 78.12
Answer:
$216 or $162 (see below)
Step-by-step explanation:
If it's 18% for 9 months (and not per year)
then
1200x0.18=$216
If it's 18% per year then
1200x0.18x0.75=$162
The correct answer to your problem is B.
y-4 = 3(x-2)
