Question

Hello, I need answers to all odd numbered questions thank you very much

Answer 1

Step-by-step explanation:

For all those miserable math lessons.....I think I can say I picked sth out of it:)

Hope that helps

Answer 2

Answer:

Question (5):

$(2x - y) + (x - 2y)i = 5 + i \\ \\ 2x - y + xi - 2yi = 5 + i$

• group imaginary terms and real terms on different sides:

$2x - y - 5 = i - xi + 2yi \\ \\ 2x - y - 5 = (1 - x + 2y)i$

• To find value of x, Imaginary part is zero

$2x - y - 5 = 0 \\ 2x - y = 5 - - - (a)$

• For Imaginary part, real part is zero:

$1 - x + 2y = 0 \\ x - 2y = 1 - - - (b)$

• solving simultaneously:

${ \boxed{ \boxed{ \: \: x = 3 \: \: }}} \: and \: { \boxed{ \boxed{ \: \: y = 1 \: \: }}}$

Question (4):

$(2x - 3) + (3y + 1)i = 7 + 10i \\ \\ 2x - 3 + 3yi + i = 7 + 10i \\ \\ 2x - 3 - 7 = 10i - 3yi - i \\ \\ 2x -10 = (9 - 3y)i$

• Group imaginary part and real part

$2x - 10 = 0 \\ 2x = 10 \\ { \boxed{ \: \: x = 5 \: \: }}$

for y:

$9 - 3y = 0 \\ 3y = 9 \\ { \boxed{ \: \: y = 3 \: \: }}$