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3 years ago

What is the slope of the line that contains the points (-4,3) and (6,-3)

1 answer:

6 0

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -4 &,& 3~) 
% (c,d)
&&(~ 6 &,& -3~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-3-3}{6-(-4)}\implies \cfrac{-3-3}{6+4}
\\\\\\
\cfrac{-6}{10}\implies -\cfrac{3}{5}$

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Write an algebraic expression for the word phrase.

vovangra [49]

Answer:

0.30 m

Step-by-step explanation:

<u>Explanation</u>:-

Given data is 30 % of m

Algebraic expression:-

The form of the algebraic expression is ax+ by +c

Given data is 30 % of m

here 'of' meaning is multiplied of given term

therefore $\frac{30}{100} X m$

The algebraic expression is 0.30 m

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3 years ago

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Answer:

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3 years ago

In a basketball game 96 points were scored. The winners scored twice as many as the losers. How many points did each team score?

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3 years ago

PLS HELP ME

Crank

Answer:

Yes it is statistical, it anticipates enough variability in responses

Step-by-step explanation:

-lukelaws

Hope I helped If I did please mark me brainliest if its wrong I am sorry!

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2 years ago

An automobile manufacturer has given its car a 52.6 miles/gallon (MPG) rating. An independent testing firm has been contracted t

Arte-miy333 [17]

Answer:

Null hypothesis: $\mu = 52.6$

Alternative hypothesis: $\mu \neq 52.6$

$z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976$

$p_v =2*P(z>1.976)=0.0482$

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

Step-by-step explanation:

Information provided

$\bar X=52.8$ represent the sample mean for the MPG of the cars

$\sigma=1.6$ represent the population standard deviation

$n=250$ sample size of cars

$\mu_o =52.6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis

We need to conduct a hypothesis in order to check if the true mean of MPG is different from 52.6 MPG, the system of hypothesis would be:

Null hypothesis: $\mu = 52.6$

Alternative hypothesis: $\mu \neq 52.6$

Since we know the population deviation the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Calculate the statistic

Replacing we have this:

$z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976$

Decision

Since is a two tailed test the p value would be:

$p_v =2*P(z>1.976)=0.0482$

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

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3 years ago