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4 years ago

(X-3)(x+2)=0 find the zeros

Mathematics

1 answer:

Ivanshal [37]4 years ago

6 0

Answer: Min = (0.5, −6.25)

Step-by-step explanation: Standard form:

x2 − x − 6 = 0

Factorization:

(x + 2)(x − 3) = 0

Solutions based on factorization:

x + 2 = 0 ⇒ x1 = −2

x − 3 = 0 ⇒ x2 = 3

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HELP QUICK. I WILL THUMBS UP

Ugo [173]

A diagram would be nice. The quick answer is C.

The first answer makes AE 8 which is twice as long as AC. I don't think the intent of the question is to use an external point.

The second one is also incorrect. This time E is in a place such that it makes AC and AE both equal and that too isn't possible.

The third one is the answer because D and E are both 1/2 the distance between the end point of the line containing them.

D is wrong because E is the midpoint of AC but D is not the midpoint of AB.

5 0

3 years ago

Read 2 more answers

a circle has a circumstance of 20. it has an arc on length 4. what is the central angle of the arc in degrees?

erastovalidia [21]

Answer:

∠72°.

Step-by-step explanation:

If a circle has a circumference of 20 and an arc with a length of 4, we can simply set up a ratio to determine the angle of the arc in degrees:

$\frac{4}{20} = \frac{x}{360}$

Cross multiply:

$1440 = 20x\\$

Divide both sides by '20':

x = 72°.

Therefore, the measure of the central angle of the arc is ∠72°.

4 0

3 years ago

I need help.. A diameter of a circle has endpoints p(-10, -2) and q(4, 6)

Phoenix [80]

A: The center is the mid point of the diameter. So, the center of the circle will be the midpoint of points P and Q. The coordinates of the midpoint are the averaged coordinates of the endpoints.

So, the x-cooardinate of the center is the average of the x-coordinates of P and Q:

$C_x = \dfrac{P_x+Q_x}{2}=\dfrac{-10+4}{2}=\dfrac{-6}{2}=-3$

Try to do the same thing with the y coordinates, and you'll get the y-coordinate $C_y$ . This first part will be over, because the circle will be point

$C=(C_x,C_y)$

B: The radius is exactly half the diameter. So, we find the length of the diameter, and we divide it by 2. To find the length of the diameter, we use the standard formula for the distance between two points:

$d=\sqrt{(P_x-Q_x)^2+(P_y-Q_y)^2}=\sqrt{(-10-4)^2+(-2-6)^2}=\sqrt{260}=2\sqrt{65}$

Divide this length by 2 and you'll get the radius.

C: At this point, we have both the radius and the coordinates of the center. The equation of the circle depends on these two parameters, and it is

$(x-C_x)^2+(y-C_y)^2=r^2$

Substitute $C_x$ and $C_y$ with the coordinates of the center (found in point A.) and $r$ with the radius (found in point B.) and you'll have the equation of the circle.