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3 years ago

How many times bigger is 80000000 than 20000

Mathematics

2 answers:

Elis [28]3 years ago

8 0

Answer:
4000 times greater

hram777 [196]3 years ago

4 0

Step-by-step explanation:

79,980,000times bigger

You might be interested in

Calculate the length b to two decimal places.

Andrej [43]

Answer:

B. 21.64

Step-by-step explanation:

We have been given a triangle and we are asked to find the length of AC (b).

We will use law of cosines to find the length of side AC.

$c^{2}=a^{2}+b^{2}-2ab \text{ cos }\theta$

Upon substituting our given values in the formula we will get,

$(AC)^{2}=15^{2}+12^{2}-2\times 15\times 12 \text{ cos}(106)$

$(AC)^{2}=225+144-360\text{ cos}(106)$

$(AC)^{2}=369-360(-0.275637355817)$

$(AC)^{2}=369+99.22944809412$

$(AC)^{2}=468.22944809412$

Upon taking square root of both sides of our equation we will be get,

$AC=\sqrt{468.22944809412}$

$AC=21.6386101238993629\approx 21.64$

Therefore, the length of b is 21.64 and option B is the correct choice.

6 0

3 years ago

What is the answer to<br> (6^-2/7^5)^-11

dusya [7]

Answer:605052^11

Step-by-step explanation:

7 0

3 years ago

1360 concert tickets were sold for a total of $13,328. If students paid $8 and non students paid $12, how many student tickets w

lyudmila [28]

748 student tickets were sold.

Step-by-step explanation:

Given,

Number of tickets sold = 1360

Revenue generated = $13328

Cost of each student ticket = $8

Cost of each non student ticket = $12

Let,

x be the number of student tickets sold

y be the number of non student tickets sold

According to given statement;

x+y=1360 Eqn 1

8x+12y=13328 Eqn 2

Multiplying Eqn 1 by 12

$12(x+y=1360)\\12x+12y=16320\ \ \ Eqn\ 3$

Subtracting Eqn 2 from Eqn 3

$(12x+12y)-(8x+12y)=16320-13328\\12x+12y-8x-12y=2992\\4x=2992\\$

Dividing both sides by 4

$\frac{4x}{4}=\frac{2992}{4}\\x=748$

748 student tickets were sold.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

5 0

3 years ago

Heeelllllppp ASAAPPPPP

Nutka1998 [239]

The answer is 351.8.

4 0

3 years ago

Read 2 more answers

If John has pairs 5 different colors pairs of socks, how many orders can he wear them in over five days? Repetition is not allow

ikadub [295]

Answer:

120 ways

Step-by-step explanation:

On the first day, John was 5 choices 5

On the second day he has 4 choices 4

On the third day he has 3 choices

On the fourth day he has 2 choices

On the fifth day he has 1 choice

5*4*3*2*1 = 120 different ways

4 0

3 years ago