Answer:
probability that Shaun loses both games
Step-by-step explanation:
Games are independent, so we find each separate probability, and multiply them.
In a chess club the probability that Shaun will beat Mike is 3/8.
So
probability that Shaun loses.
The probability that Shaun will beat Tim is 5/7 .
So
probability that Shaun loses.
What is the probability that Shaun loses both games?
This is:

probability that Shaun loses both games
Greater than is the answer
Answer:
w= 8
Step-by-step explanation:
180-90= 90
(5w + 1) + (7w- 7) = 90
solve
w= 8
Step-by-step explanation:

Now for another

Hope it will help :)❤
Answer:
b = 3
Step-by-step explanation:
Isolate the variable, b. Note the equal sign, what you do to one side, you do to the other:
First, distribute 3 to all terms within the parenthesis:
3(3x + 1) =
3 * 3x = 9x
3 * 1 = 3
9x + b = 9x + 3
Isolate the variable, b. Subtract 9x from both sides:
9x (-9x) + b = 9x (-9x) + 3
b = 3
3 is your value for b.
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