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Karo-lina-s [1.5K]
3 years ago
15

Find the rectangular coordinates of the point (sqrt3,pi/6)

Mathematics
1 answer:
madreJ [45]3 years ago
5 0

Answer:

(x, y) = \left(\frac{3}{2}, \frac{\sqrt{3}}{2}\right)

Step-by-step explanation:

The rectangular coordinates of the point are:

(x,y) = \left(\sqrt{3}\cdot \cos\frac{\pi}{6}, \sqrt{3}\cdot \sin\frac{\pi}{6}\right)

(x, y) = \left(\frac{3}{2}, \frac{\sqrt{3}}{2}\right)

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What is the probability of rolling a dice and getting either a 1 or 2 and flipping a coin and getting a heads?
EastWind [94]

Answer:

1/3 and 1/2

Step-by-step explanation:

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Which of the following slopes show that the set of points C(1, 1), D(3, -4), E(5, 8) are not collinear?
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Determine the end behavior of the polynomial function. f(x)=-3x^4-2x^3+2x^2+ 3x +5 a) falls to the left and rises to the right b
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Answer:

Option b is correct

Step-by-step explanation:

In order to check the end behavior of a  polynomial function we   just check the leading term and its coefficient and the procedure is as  follows:

Here we can see that highest exponent of the polynomial function is 4

therefore degree of the polynomial is 4. and therefore  -3x^4 is leading term.  

because of even degree it will be same from both ends that is either both sides rises or both sides falls. Since number in the front of  leading is negative therefore it falls at both ends. that is  falls to  the left and falls to the right.

therefore option b is correct.

8 0
4 years ago
What is the difference in speed between two cars when one traveled 175 km in 4 hours and the other traveled the same distance in
vovangra [49]
<h3>Given :</h3>
  • Distance = 175
  • Time 1 = 4 hours

\\  \\

<h3>To find:</h3>
  • Different between two speeds when distance is same.

\\  \\

<h3>Solution:</h3>

<u>Part</u><u> </u><u>1</u><u> </u><u>:</u>

In first part we will find speed 1 in which time is 4 hours

we know:-

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

So:-

\dashrightarrow\sf speed_1 =  \dfrac{distance}{time_1}

\\  \\

\dashrightarrow\sf speed_1 =  \dfrac{175}{4}

\\  \\

\dashrightarrow\bf speed_1 =  43.75 \: km {h}^{ - 1}

<u>Part 2</u>

In first part we will find speed 2 in which time is 3 hours

Again:

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{distance}{time_2}

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{175}{3}

\\  \\

\dashrightarrow\bf speed_2 = 58.33kmh^{-1}

\\  \\

<u>Part 3</u>

In this part we will find different between speed 1 and speed 2

\bigstar  \boxed{\rm Difference = speed_2 - speed_1}

\\  \\

So :

\dashrightarrow\sf Difference = speed_2 - speed_1 \\

\\  \\

\dashrightarrow\sf Difference =58.33 - 43.75\\

\\  \\

\dashrightarrow\bf Difference =14.58kmh^{-1}\\

\\  \\

\therefore \underline {\textsf{\textbf{Difference in speed between two cars is \red{14.58km/h}}}}

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