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uysha [10]
2 years ago
14

On the first day of a road trip, Roberto traveled 213 miles from home. On the second day, he drove 149 miles farther. How many m

iles from home is Roberto at the end of his second day? * 1 point 1. 362 miles 2. 213 miles 3. 149 miles 4.63 miles
Mathematics
1 answer:
jek_recluse [69]2 years ago
4 0

The answer would be 362 miles

add the number of miles from day one and day two

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Graph the function. Describe its position relative to the graph of the indicated function
sweet [91]

Answer:

C

Step-by-step explanation:

If the parent function is function y=f(x) and a>0, then

  • the graph of the function y=f(x-a) is translated a units to the right graph of the parent function;
  • the graph of the function y=f(x+a) is translated a units to the left graph of the parent function;
  • the graph of the function y=f(x)+a is translated a units up graph of the parent function;
  • the graph of the function y=f(x)-a is translated a units down graph of the parent function.

In your case, the grapgh of the function y=2^x+2 is translated 2 units up the graph of the function y=2^x.

6 0
3 years ago
Read 2 more answers
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
HELP help HELP help HELP help HELP help HELP help HELP help HELP help
Morgarella [4.7K]

\text{mass of freight train} = 9.98 \times  {10}^{6} kg

\text{mass of aircraft carrier} = 7.3 \times  {10}^{7}  \: kg

\text{difference of masses of aircraft and train: } \\  \\ 7.3 \times  {10}^{7}  - 9.98 \times  {10}^{6}  \\  \\  = 73 \times  {10}^{6}  - 9.98 \times  {10}^{6}

= (73 - 9.98 )\times  {10}^{6}  \\  \\  = 63.02 \times  {10}^{6}  \\  \\  = 6.302 \times  {10}^{6}  \: kg \\  \\  \approx 6.3 \times  {10}^{6}  \: kg

Approximately, aircraft carrier is 6.3 × 10^6 kg heavier than the freight train.
7 0
3 years ago
Given that <img src="https://tex.z-dn.net/?f=a%5Cneq%20b" id="TexFormula1" title="a\neq b" alt="a\neq b" align="absmiddle" class
xz_007 [3.2K]

Answer:

Step-by-step explanation:

√a+√b=√(a+b)

squaring

a+b+2√a√b=a+b

or 2√a√b=0

which is possible only if a=0 or b=0

Both a and b can't be zero as a≠b

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3 years ago
Find the value of x in the following quadrilateral
vlabodo [156]

Answer:

The answer is 63.31

Step-by-step explanation:

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3 years ago
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