All categories

3 years ago

What is larger? 70mg or 7g please help need now

Mathematics

2 answers:

Ratling [72]3 years ago

6 0

Answer: 7 g

1 g = 1000 mg

7g = 7000 mg

WKT 7000 mg is greater than 70 mg

Hope it hepls

babunello [35]3 years ago

3 0

Answer:

7 g.

Step-by-step explanation:

7g = 7000 mg

You might be interested in

write a slope-intercept equation for a line passing through the point (2,8) that is parallel to y=7/5x+7. Then weite a second eq

Arisa [49]

Answer:

y=7/5x+26/5 and y=-5/7x+66/7

Step-by-step explanation:

if it's parallel, it needs to have the same slope, so the equation is y=7/5x+26/5. the perpendicular line is y=-5/7x+66/7.

6 0

3 years ago

Can someone plzzz help me with numbers 15 and 16 olzzz show work cuz I don’t understand plzz

sertanlavr [38]

Pythagoras says
a squared = b squared + c squared so
xsquared= 21 squared +17 squared
x squared = 441 + 34
x squared = 475
x = squared root of 475
x= 21.79mi

6 0

3 years ago

Solve this question

Andrews [41]

-20=-4x-6x
First combine like terms.
-20=-10x
Divide by -10 on both sides
X=2

3 0

3 years ago

Solve for b:4 = -2/3(5) + b

saveliy_v [14]

Answer:

$\frac{22}{3}$ = b

7 $\frac{1}{3}$ = b

(they are the same value, just different ways of writing it)

Step-by-step explanation:

4 = - $\frac{2}{3}$ (5) + b

simplify

4 = - $\frac{10}{3}$ + b

now use inverse operations

4 = - $\frac{10}{3}$ + b

+ $\frac{10}{3}$ + $\frac{10}{3}$

$\frac{22}{3}$ = b

4 0

4 years ago

Use the Factor Theorem and synthetic division to show x + 5 is a factor of f(x) = 2x3 + 7x2 − 14x + 5

olga2289 [7]

Answer:

Factor theorem: $f(-5) = 0$ .

Synthetic division: $f(x) = (x + 5)\, (2\, x^2 -3\, x + 1)$ .

Step-by-step explanation:

<h3>Factor Theorem</h3>

By the factor theorem, a monomial of the form $(x - a)$ (where $a$ is a constant) is a factor of polynomial $f(x)$ if and only if $f(a) = 0$ .

In this question, the monomial is $(x + 5)$ , which is equivalently $(x - (-5))$ . $a = -5$ .

$\begin{aligned}& f(-5) \\ &= 2 \times (-5)^{3} + 7 \times (-5)^{2}- 14\times (-5) + 5\\ &= -250 + 175 + 70 + 5 \\ &= 0\end{aligned}$ .

Hence, by the factor theorem, $(x + 5)$ , which is equivalent to $(x - (-5))$ , is a factor of $f(x)$ .

<h3>Synthetic Division</h3>

$\begin{aligned}& f(x) \\ &= 2\, x^{3} + 7\, x^{2} - 14\, x + 5 \\ &= \underbrace{(x + 5) \, (2\, x^2)}_{2\, x^{3} + 10\, x^{2}} - 3\, x^{2} - 14\, x + 5 \\ &= \underbrace{(x + 5) \, (2\, x^2)}_{2\, x^{3} + 10\, x^{2}} + \underbrace{(x + 5)\, (-3\, x)}_{-3\, x^{2} - 15\, x} + (x + 5) \\ &= (x + 5)\, (2\, x^{2} - 3\, x + 1)\end{aligned}$ .

The remainder is $0$ when dividing $f(x)$ by $(x + 5)$ . Hence, $(x + 5)\!$ is a factor of $f(x)\!$ .

6 0

4 years ago