![\sqrt[8]{48^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B8%5D%7B48%5E4%7D%20)
can be rewritten as

to the

power:

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

This is equivalent to

, so now, we just simplify:

So:
9514 1404 393
Answer:
2) 1/3
Step-by-step explanation:
The repeating decimal can be converted to a fraction by multiplying it by 10^n and subtracting the original value. n = number of repeating digits. This process cancels all of the repeating digits, so you can find the equivalent fraction.

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Your calculator can help you answer this:
1/5 = 0.2
1/3 = 0.333.... (repeating) . . . . the number you're looking for
3/10 = 0.3
3/5 = 0.6
Step-by-step explanation:
with your square root symbol I never know what is inside the square root and what is possibly outside.
so, I can only guess and see what comes close.
f(x) = 2x² + x - 1
g(x) = sqrt(2x - 1) ??? is that so ?
h(x) = -2
2g(f(x)) + h(x)
g(f(x)) means that the whole f(x) expression is used as x in g(x).
the whole combined function is then
2×sqrt(2(2x² + x - 1) - 1) - 2
2×sqrt(4x² + 2x - 2 - 1) - 2
2×sqrt(4x² + 2x - 3) - 2
and if I am not mistaken, then this is the solution you mentioned at the beginning (if I try to read between the typos and missing info).
this is how people get to this.
do you understand it now ? or is there still something unclear ?
Answer:
0,1,2,3
Step-by-step explanation: