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adelina 88 [10]
3 years ago
14

How do you write 9.58 as a mixed number

Mathematics
2 answers:
kodGreya [7K]3 years ago
8 0
9 58/100 in mixed number form
tia_tia [17]3 years ago
6 0
9 58/100 or simplified it is 9 29/50

I hope this helps!
If you want an explanation don't be afraid to ask!
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Simplify each ratio. <br><br> 1) 40:15
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Answer:

8:3

Step-by-step explanation:

,,,,lol hope it helps i don't know how to explain,,, I guess its just dividing you know like 15÷5= 3 so on

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Solve the inequality
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(2.5+3)

Step-by-step explanation:

im not 100% sure though sorry

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Which of the following statements about the mean is false?
Harlamova29_29 [7]

Answer:

The value of the mean reflects both the number and the value of cases. is false

Step-by-step explanation:

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3 years ago
To investigate whether or not sexism was present in the workplace, 48 male bank supervisors were each given a personnel file and
Volgvan
There is a clear bias. It is important however to not look at how many women got promoted with respect to men but which proportion of each subset got promoted. In the man files, 21/24 got promoted; this is a very high percentage, equal to 87.5%. Nonetheless, regarding women, 14/24 got promoted, 58,3%, barely over half of them. Hence, we conclude that there is a significant bias that favors male workers.
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3 years ago
PLEASE HELP!
wariber [46]

Answer: The maximum value: P = 6x + 7y - 2 is 84 at (5,8).

Step-by-step explanation:

Here, Object of constraint P(max) = 6x + 7y - 2.

And, the system of constraints,

x≤5,   y≤(1/5)x + 7,   x≥0,   y≥0        

Since, x= 5 is a line parallel to y-axis.

And  at origin it is giving 0≤5 ( false)

Thus the area of inequality x≤5 does not contain the origin.

Now, x -intercept and y-intercept of line y=(1/5)x + 7 are (-35,0) and (0, 7) respectively.

Also, at (0, 0),  0 ≤(1/5)×0 + 7 (true)

Therefore, inequality y≤(1/5)x + 7 will contain the origin.

Now, x≥0,   y≥0  shows the first quadrant.

Thus, we get feasible region ABCD.

In which at A≡(0,7), P = 49.

At B≡(5,8), P= 84,

At C≡(5,0), P= 30,

And, D≡(0,0), P= 0

Therefore at B, P is maximum.

8 0
3 years ago
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