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3 years ago

The characteristics of interest, determining the types of data that are being collected.

Mathematics

1 answer:

wel3 years ago

3 0

Answer:

Step-by-step explanation:

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Simplify 4 3 square root 64

Ierofanga [76]

Answer:

$\large\boxed{4\sqrt[3]{64}=16}$

Step-by-step explanation:

$\sqrt[3]{a}=b\iff b^3=a\\\\4\sqrt[3]{64}=(4)(4)=16\\\\\sqrt[3]{64}=4\ \text{because}\ 4^3=64$

8 0

3 years ago

A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?

AlekseyPX

Answer:

The width of the sandbox is $42\frac{2}{3} \ ft$ .

Step-by-step explanation:

Given,

Area of the sandbox = $10\frac{2}{3}=\frac{32}{3}\ ft^2$

Length = $\frac{1}{4}\ ft$

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

$Area = Length\times Width$

On substituting the given values, we get;

$\frac{1}{4}\times w=\frac{32}{3}\\$

By cross multiplication method, we get;

$w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft$

Hence The width of the sandbox is $42\frac{2}{3} \ ft$ .

5 0

3 years ago

4 - |-2|=<br> what is the answer please

Gelneren [198K]

The answer is 2 hope it helps

5 0

3 years ago

Use substitution to solve the following system of equations.

Diano4ka-milaya [45]

$d+e-f=-3 \\
e=f+d+7 \\
f=2e-6 \\ \\
\hbox{substitute 2e-6 for f in the 2nd equation and solve for e:} \\
e=2e-6+d+7 \\
e=2e+d+1 \ \ \ |-2e \\
-e=d+1 \ \ \ |\times (-1) \\
e=-d-1 \\ \\
\hbox{substitute -d-1 for e in the 3rd equation and solve for f:} \\
f=2(-d-1)-6 \\
f=-2d-2-6 \\
f=-2d-8$

$\hbox{substitute -d-1 for e and -2d-8 for f in the 1st equation and solve for d:} \\
d+(-d-1)-(-2d-8)=-3 \\
d-d-1+2d+8=-3 \\
2d+7=-3 \ \ \ |-7 \\
2d=-10 \ \ \ |\div 2 \\
d=-5 \\ \\ e=-d-1=-(-5)-1=5-1=4 \\ \\
f=-2d-8=-2 \times (-5)-8=10-8=2 \\ \\
\boxed{d=-5} \\ \boxed{e=4} \\ \boxed{f=2} \\
\hbox{answer D}$

5 0

3 years ago

Pls anyone help me with this question God PLSSS

Sindrei [870]

Answer:

(6,4)

Step-by-step explanation:

Hope it helps you.......

5 0

3 years ago