Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:
Hence the bounds of the interval are found as follows:
The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
Answer:
y=0.75x+3.75
Step-by-step explanation:
The slope is
Substituting into point-slope form,
y - 6 = 0.75(x - 3)
y - 6 = 0.75x - 2.25
y = 0.75x + 3.75
5/12 is the simplified fraction for 30/72 by using the GCD or HCF method. 5/12 is simplified fraction for 30/72 by using the prime fractorization method.
Answer:
3/2 or 1 1/2
Step-by-step explanation:
5÷3 1/3
5/1 ÷ 10/3 because you have to get it into an improper fraction form in order to divide
5/1 × 3/10 because you have to multiply the first number by the reciprocal
5 and 10 cancel out so you would have 2 at the bottom
3/2 or 1 1/2
Answer:
10 people lesser.
Step-by-step explanation:
Initially, it 15 people get off but 9 people get picked up, hence losing 6 people. If 4 more people get off, it has then lost 10 people total.
The original number of passengers on the bus decreased by 10 after the second stop
Assume that the total passengers on the bus before 2:30 was x
Now, at 2:30:
15 passengers got off and 9 got on.
This means that:
number of passengers = x - 15 + 9
number of passengers = x -6
10 minutes later:
4 passengers got off the bus
This means that:
number of passengers = (x-6) - 4
number of passengers = x - 10
The original number of passengers on the bus decreased by 10 after the second stop.
