The expression for five groups of a number added to seventeen.
Let the number be X
Five groups of the number will be 5X
The required expression will be
5(X) +17
A40=a1 +(40-1)r
in this case r is 3 beceause -2+3 will be 1 etc
a40=-2 +39*3
Answer: x = (sqrt(7) + 2)/3 and
x = ( – sqrt(7) + 2)/3
Explanation:
3x^2 - 4x - 1 = 0
Divide both sides by 3:
3x^2/3 - 4/3x - 1/3 = 0/3
x^2 - 4/3x - 1/3 = 0
x^2 - 4/3x = 1/3
x^2 - 4/3x + (2/3)^2 = 1/3 + (2/3)^2
(x - 2/3)^2 = 1/3 + 4/9
(x - 2/3)^2 = 7/9
Sqrt both sides:
x - 2/3 = sqrt (7/9)
x - 2/3 = |sqrt(7)/3|
Set x -2/3 = sqrt(7)/3
=> x = (sqrt(7) + 2)/3
Set x - 2/3 = - sqrt(7)/3
=> x = ( - sqrt(7) + 2)/3
Answer:
D y-8 +2 ≤ -2+2
Step-by-step explanation:
y-8 ≤ -2
Add 2 to each side
y-8 +2 ≤ -2+2
Answer: 10+30=40 :)
Step-by-step explanation:
