Answer:
Therefore 53.05 mg will remain of the given radioactive substance after 35 hours.
Step-by-step explanation:
Radioactive Decay:
Integrating both sides
[ ]
When t=0, = initial amount
Therefore the decay equation is
Given that, = Initial amount of the radioactive substance= 140 mg
After 25 hours, 70 mg of substance remains.
N= 70 mg, t=25 hours
[ ]
The decay equation becomes
Now putting t= 35
= 53.05 mg
Therefore 53.05 mg will remain of the given radioactive substance after 35 hours.
Answer:
a) 0.3277
b) 0.0128
Step-by-step explanation:
We are given the following information in the question:
N(2750, 560).
Mean, μ = 2750
Standard Deviation, σ = 560
We are given that the distribution of distribution of birth weights is a bell shaped distribution that is a normal distribution.
Formula:
a) P (less than 2500 grams)
P(x < 2500)
Calculation the value from standard normal z table, we have,
b) P ((less than 1500 grams)
P(x < 1500)
Calculation the value from standard normal z table, we have,
Answer:
c.) 4 2/3
Step-by-step explanation:
look at the screenshot below it'll explain the answer
Answer:
-5
Step-by-step explanation:
Find the number with the equation 6(x + 8) = 18
solve for x to get -5
120 + 0.40m = 50 + 0.50m
120 - 50 = 0.50m - 0.40m
70 = 0.10m
70/0.10 = m
700 = m....they will be the same at 700 miles