The derivative, f'(x) = 6x^2+1, is never negative, so f(x) is monotonic, hence invertible.
f'(-2) = 6(-2)²+1 = 25
If point (-2, -26) is on the graph of function f(x), and the slope is 25 there, then (-26, -2) is on the graph of f⁻¹(x), and the slope is 1/25 there. The equation of the tangent line throught that point can be written in point-slope form as
... y +2 = (1/25)(x +26)
Answer:
D is Permutation with repetition right
Step-by-step explanation:
Answer:
9
41/4
23/2
51/4
14
Step-by-step explanation:
The first term is the first term that is given. Just copy it.
Each next term is the previous term plus the common difference.
First term: a_1 = 9
Second term: a_2 = 9 + 5/4 = 36/4 + 5/4 = 41/4
Third term: a_3 = 41/4 + 5/4 = 46/4 = 23/2
Fourth term: a_4 = 46/4 + 5/4 = 51/4
Fifth term: a_5 = 51/4 + 5/4 = 56/4 = 14
Answer:
Its D
Step-by-step explanation:
(a+b)² can also be written as (a+b) (a+b). When you expand this you get a²+2ab+b²
(a-b)² can also be written as (a-b) (a-b). When expanded this gives a²-2ab-b2
As you can see, this leads to different coefficients of the 'ab' values: for (a+B) ² its 2 for (a-b) ² its - 2
