Since both 2 and 5 are prime numbers, there are no multiples for the fraction 2/5.
Given that,
the two numbers are consecutive
The two numbers are
x and x + 1
Sum of the numbers = 81
x + (x + 1) = 81
x + x + 1 = 81
2x = 81 - 1
2x = 80
x = 80/2
x = 40
Therefore, <em>the two numbers are</em> x = 40 and x + 1 = 41
What is this question supposed to be?
<h2>
<u>Sol</u><u>ution</u><u>:</u></h2>
Equation: x² + 10x + 21
<u>Step</u><u> </u><u>1</u><u>:</u> Find two numbers that can add up to 10 and be multiplied to 21. We have: 7 & 3, in the sense that 7+3=10, and 7×3=21. Replacing 10 with 7+3, the equation is now → x² + 7x + 3x + 21
<u>Step</u><u> </u><u>2</u><u>:</u> Get the new equation bracketed → (x² + 7x) (+3x + 21)
<u>Step</u><u> </u><u>3</u><u>:</u> Use 'x' in the equation. For the first part, we have 'x'. x² = x × x so, bring out one x out side the bracket, divide 7x by = 7 → x (x +7). Do the same for the second part by dividing 21 by 3 = 7, and then bringing out 3 from the bracket → 3 (x + 7).
Bringing everything together, we have: x(x+7) +3(x+7) → (x+3) (x+7)
<h3>
<u>Final</u><u> </u><u>ans</u><u>wer</u><u>:</u></h3>
(x+3) (x+7)
<h3 />
The formula for graphing is y=mx+b, where m is the slope and b is the slope-intercept (where the line is at x=0). In this case, the slope is 10. Hope this helps and please give branliest!
