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3 years ago

Help Please! Help me answer these questions #21, 23, 25

Mathematics

1 answer:

Gala2k [10]3 years ago

6 0

21. There are 4 aces and 4 fours. p = 8/52 = 2/13

23. There are 26 black cards and 6 red picture cards. p = 32/52 = 8/13

25. There are 13 clubs and 15 more cards 5 or less. p = 28/52 = 7/13

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Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

2 years ago

Figure ABCD is a kite

Mars2501 [29]

The kite is symmetric about line segment BD.
Therefore
AB = BC
3x + 1 = 22
3x = 22 - 1 = 21
x = 21/3 = 7

Similarly,
AD = CD by symmetry
Therefore
4x = CD
4*7 = CD
28 = CD, the required line segment

Answer: 28

4 0

2 years ago

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I need help with this plzzz

Advocard [28]

I think it is BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB

3 0

2 years ago

Read 2 more answers

The equation of line L is y=5x+1

vovikov84 [41]

Answer:

see explanation

Step-by-step explanation:

Parallel lines have equal slopes.

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

L₁ is y = 5x + 1 ← in slope- intercept form

with slope m = 5

L₂ is 2y - 10x + 3 = 0 ( subtract - 10x + 3 from both sides )

2y = 10x - 3 ( divide all terms by 2 )

y = 5x - $\frac{3}{2}$ ← in slope- intercept form

with slope m = 5

Since L₁ and L₂ have equal slopes then they are parallel lines

3 0

2 years ago

!!help!!

IrinaVladis [17]

Answer:

−

(5)(8)x

−35x+2

Step-by-step explanation:

4 0

2 years ago