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liubo4ka [24]
2 years ago
12

Please help due tonight!

Mathematics
1 answer:
Kamila [148]2 years ago
7 0
Just remember that vertical angles are congruent and have same degree. Straight lines add up to 180 degrees.

G = 115 degrees (vertical angle)
K = 131 degrees (vertical angle)
h = 180-115 = 65 degrees
m = 180 - 131 = 49 degrees
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I need help on this question
anyanavicka [17]

Remark

There is a very quick way to do this. Scan the numbers. You want 75 to be the mean, so make it so. Then figure out how many up or down you go from 75. I'll make a list of the givens.

72 - 3 72 is three down from 75 so call it - 3

75 0 That is your desired average so it adds nothing to the score.

74 -1 It is one down from 75, so call it -1

76 +1 It is one up from 75

76 +1 it is one up from 75

75 adds 0.

-3 - 1 + 1 + 1 = - 2

That comes - 2/7 which means that you need a score just under 75. So 75 will give you the right average of 75

Answer B <<<<<

7 0
2 years ago
How can you find the median when the number is not in the middle
lara [203]
You add the two numbers and whatever you get you then divide it by 2
8 0
2 years ago
Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of
GenaCL600 [577]

Close off the hemisphere S by attaching to it the disk D of radius 3 centered at the origin in the plane z=0. By the divergence theorem, we have

\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV

where R is the interior of the joined surfaces S\cup D.

Compute the divergence of \vec F:

\mathrm{div}\vec F(x,y,z)=\dfrac{\partial(xz^2)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial k}=z^2+y^2+x^2

Compute the integral of the divergence over R. Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\begin{cases}x^2+y^2+z^2=\rho^2\\\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi\end{cases}

So the volume integral is

\displaystyle\iiint_Rx^2+y^2+z^2\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{486\pi}5

From this we need to subtract the contribution of

\displaystyle\iint_D\vec F(x,y,z)\cdot\mathrm d\vec S

that is, the integral of \vec F over the disk, oriented downward. Since z=0 in D, we have

\vec F(x,y,0)=\dfrac{y^3}3\,\vec\jmath+y^2\,\vec k

Parameterize D by

\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

where 0\le u\le 3 and 0\le v\le2\pi. Take the normal vector to be

\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=-u\,\vec k

Then taking the dot product of \vec F with the normal vector gives

\vec F(x(u,v),y(u,v),0)\cdot(-u\,\vec k)=-y(u,v)^2u=-u^3\sin^2v

So the contribution of integrating \vec F over D is

\displaystyle\int_0^{2\pi}\int_0^3-u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac{81\pi}4

and the value of the integral we want is

(integral of divergence of <em>F</em>) - (integral over <em>D</em>) = integral over <em>S</em>

==>  486π/5 - (-81π/4) = 2349π/20

5 0
3 years ago
The sum of eight and a number, x, is three.
Tresset [83]

Answer:

x= -5

Step-by-step explanation:

8+(-5)=3

7 0
3 years ago
(2x-1)(x+2y-3)=<br> Mohon dijawab
laiz [17]
(2x - 1)(x + 2y - 3) =
2x(x + 2y - 3) + (-1)(x + 2y - 3) =
2x^2 + 4xy - 6x - x - 2y + 3 =
2x^2 + 4xy - 7x - 2y + 3
6 0
2 years ago
Read 2 more answers
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