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Vesna [10]
3 years ago
7

What should you do first to write 3.775×10−6 in standard​ form? A. Move the decimal point 6 places to the left. B. Move the deci

mal point 5 places to the right. C. Move the decimal point 6 places to the right. D. Move the decimal point 5 places to the left.
Mathematics
1 answer:
NemiM [27]3 years ago
7 0

Answer:

It is in standard form, unless you say you want to write it in whole number form, move it six points to the left

Step-by-step explanation:

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145,973 Is decimaled in 145.
14.5
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Solve the equation<br> 7x25=30
oksian1 [2.3K]

Answer:

x = -(-30/7)^(1/25) or x = (30/7)^(1/25) or x = (-1)^(2/25) (30/7)^(1/25) or x = -(-1)^(3/25) (30/7)^(1/25) or x = (-1)^(4/25) (30/7)^(1/25) or x = -(-1)^(1/5) (30/7)^(1/25) or x = (-1)^(6/25) (30/7)^(1/25) or x = -(-1)^(7/25) (30/7)^(1/25) or x = (-1)^(8/25) (30/7)^(1/25) or x = -(-1)^(9/25) (30/7)^(1/25) or x = (-1)^(2/5) (30/7)^(1/25) or x = -(-1)^(11/25) (30/7)^(1/25) or x = (-1)^(12/25) (30/7)^(1/25) or x = -(-1)^(13/25) (30/7)^(1/25) or x = (-1)^(14/25) (30/7)^(1/25) or x = -(-1)^(3/5) (30/7)^(1/25) or x = (-1)^(16/25) (30/7)^(1/25) or x = -(-1)^(17/25) (30/7)^(1/25) or x = (-1)^(18/25) (30/7)^(1/25) or x = -(-1)^(19/25) (30/7)^(1/25) or x = (-1)^(4/5) (30/7)^(1/25) or x = -(-1)^(21/25) (30/7)^(1/25) or x = (-1)^(22/25) (30/7)^(1/25) or x = -(-1)^(23/25) (30/7)^(1/25) or x = (-1)^(24/25) (30/7)^(1/25)

Step-by-step explanation:

Solve for x:

7 x^25 = 30

Hint: | Divide by an appropriate factor to make the coefficient of x^25 equal to 1.

Divide both sides by 7:

x^25 = 30/7

Hint: | Take 25^th roots of both sides.

Taking 25^th roots gives (30/7)^(1/25) times the 25^th roots of unity:

Answer: x = -(-30/7)^(1/25) or x = (30/7)^(1/25) or x = (-1)^(2/25) (30/7)^(1/25) or x = -(-1)^(3/25) (30/7)^(1/25) or x = (-1)^(4/25) (30/7)^(1/25) or x = -(-1)^(1/5) (30/7)^(1/25) or x = (-1)^(6/25) (30/7)^(1/25) or x = -(-1)^(7/25) (30/7)^(1/25) or x = (-1)^(8/25) (30/7)^(1/25) or x = -(-1)^(9/25) (30/7)^(1/25) or x = (-1)^(2/5) (30/7)^(1/25) or x = -(-1)^(11/25) (30/7)^(1/25) or x = (-1)^(12/25) (30/7)^(1/25) or x = -(-1)^(13/25) (30/7)^(1/25) or x = (-1)^(14/25) (30/7)^(1/25) or x = -(-1)^(3/5) (30/7)^(1/25) or x = (-1)^(16/25) (30/7)^(1/25) or x = -(-1)^(17/25) (30/7)^(1/25) or x = (-1)^(18/25) (30/7)^(1/25) or x = -(-1)^(19/25) (30/7)^(1/25) or x = (-1)^(4/5) (30/7)^(1/25) or x = -(-1)^(21/25) (30/7)^(1/25) or x = (-1)^(22/25) (30/7)^(1/25) or x = -(-1)^(23/25) (30/7)^(1/25) or x = (-1)^(24/25) (30/7)^(1/25)

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A segment has endpoints with coordinates - 3 and 4. What is the coordinate of the segment's midpoint?
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Step-by-step explanation:

The midpoint is the average of the end points:

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