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3 years ago

Helpppppppppppppppppppppppppppppp! please someone?

Mathematics

2 answers:

almond37 [142]3 years ago

5 0

Step-by-step explanation:

$- \frac{16}{25} \div ( - \frac{4}{5} ) \\ - \frac{16}{25 } \div ( - \frac{4}{5} \times 5) \\ - \frac{16}{25 } \div ( - \frac{20}{25} ) \\ - \frac{16}{25} \times - \frac{25}{20} \\ \frac{4}{5} \\ answer \: is \: = \frac{4}{5} \\$

I hope this helps you

Minchanka [31]3 years ago

4 0

Answer:

$- \frac{16}{ 25 } \div ( - \frac{4}{5} ) = \frac{16}{25} \times \frac{5}{4} = \frac{4}{5} \:or \: 0.8$

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Which of the following is the solution set for the conjunction –6 < 4x + 2 < 6? x>−32 and x<32 x >–2 and x < 1

alisha [4.7K]

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<em><u>Solution:</u></em>

<em><u>Given conjunction is:</u></em>

$-6$

We have to find the solution set

<em><u>Let us solve the given conjuction</u></em>

$\mathrm{If}\:a$

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<h3><em><u>Let us first solve -6 < 4x + 2</u></em></h3>

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$\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}\\\\4x+2-2>-6-2\\\\\mathrm{Simplify}\\\\4x>-8\\\\\mathrm{Divide\:both\:sides\:by\:}4\\\\\frac{4x}{4}>\frac{-8}{4}$

$x>-2$

<h3><u><em>Now let us solve 4x + 2 < 6</em></u></h3>

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$\mathrm{Combine\:the\:intervals}$

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$Merge\:Overlapping\:Intervals$

$-2$

<h3><u>Thus the solution set for –6 < 4x + 2 < 6 is:</u></h3>

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3 0

3 years ago

What is the solution to the inequality? -2/3(2x - 1/2) ≤ 1/5x - 1 Express your answer in interval notation.

almond37 [142]

ANSWER

$-\frac{2}{3}(2x-\frac{1}{2})\le \frac{1}{5}x-1$

Multiply through by LCM of 15

$(15) \times -\frac{2}{3}(2x-\frac{1}{2})\le 15(\frac{1}{5}x-1)$

$-10(2x-\frac{1}{2})\le 3x-15$

Expand brackets to obtain,

$-20x+5\le 3x-15$

Group like terms

$15+5\le 20x+3x$

$20\le 23x$

$\frac{20}{23}\le x$

$x\ge \frac{20}{23}$

In interval form it is written as

$[\frac{20}{23}, \infty)$

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3 years ago

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RSB [31]

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