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enyata [817]
3 years ago
15

A student found the slope of a line that passes through the points (3,15) and (5,9) to be -1/3. what mistake did he make

Mathematics
1 answer:
Vlad [161]3 years ago
4 0

He didn't do it as rise over run, or y2-y1/x2-x1

He did it reverse, which is incorrect.

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Adult tickets: $27 Child tickets: $16
VARVARA [1.3K]

Answer:

x= 1 y = 375

Step-by-step explanation:

27 = 1 adult

16 = 1 child

16 divided by 400 = 25

25 - 400 = 375

375 kids and 1 adult

<h3>I HOPE THIS HELPED IT WAS CONFUSING</h3>
6 0
2 years ago
Which of the algebraic expressions are not linear expressions? Select all that apply. a. 3x - 2 b. -9y c. -7x^2^ + 4x d. -1/2x^2
Sedaia [141]

Answer:

c, d and e

Step-by-step explanation:

A linear expression is an expression in which sum of exponents of variables is at most 1 in each of its terms.

Option a: 3x - 2

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option b: -9y

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option c: -7x^2 + 4x

Here, the highest exponent of the variable is 2.

So, it is NOT a linear expression.

Option d: -\frac{1}{2} x^2

Here, the exponent of the variable is 2.

So, it is NOT a linear expression.

Option e: 8xy

Here, sum of exponents of variables is 2.

So, it is NOT a linear expression.

Hence, c, d and e are NOT algebraic expressions.

6 0
3 years ago
Help!! Which of the following best represents Z1 • Z2 select all that apply
AURORKA [14]

z_1=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)

z_2=\sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)

\cos \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}

\sin \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}

\cos \left(\frac{3\pi }{4}\right)=-\frac{\sqrt{2}}{2}

\sin \left(\frac{3\pi }{4}\right)=\frac{\sqrt{2}}{2}\\

Z_1*Z_2=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)\cdot \sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)

=\sqrt{3}\left(\frac{\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)\cdot \sqrt{6}\left(\frac{-\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)

On simplifying, we get

Z_1* Z_2 =-3\sqrt{2}

<h2>Therefore, correct option is  1st option.</h2>
3 0
3 years ago
Find the difference . <br>6 3/5 - 4 3/10<br>A. 2 0/5 <br>B. 2 1/5<br>C. 2 3/10<br>D. 10 9/10
pochemuha
Make improper fractions.

33/5 - 43/10

Find a common denominator, in this case it is 10.

66/10 - 43/10 = 23/10

This can be simplified to 2  3/10

Hope this helps!
6 0
3 years ago
Read 2 more answers
Using the numbers 2,0,1,9 in order what exoression do you make to equal 6
alexgriva [62]

Answer: 9-(0+1+2)


Step-by-step explanation:

We have given the numbers = 2,0,1,9

We can use addition and subtraction operation to the given numbers such that the answer will be equals to 6.

We can add 2 ,0 and 1 and then subtract from 9 , we will get 6.

So the required expression can be

9-(0+1+2)\\=9-(3)\\=9-3\\=6

hence, the required expression can be 9-(0+1+2)



6 0
3 years ago
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