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3 years ago

The weight of the paper clip is 1.0025 grams. Find the number of significant digits in the measurement

Mathematics

2 answers:

AURORKA [14]3 years ago

8 0

Answer: There are 5 sig figs in 1.0025

Step-by-step explanation:

With significant figures, any number other then 0 is a significant figure. The two zeros are significant because they are followed by more numbers. If the number was 1.000, there would only be one sig fig.

Hope this helps!

My name is Ann [436]3 years ago

6 0

5 significant figures.

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When it's a right triangle, its the long piece that isn't a part of the legs of the right angle.

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2 years ago

Is 1/3 greater than , less than or equal to 0.33

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Equal to. 1 divided by 3 is equal to .33etc.

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3 years ago

Read 2 more answers

I need a lot of help with this problem lol. I need help finding the mean, median, mode, and range for the numbers .06, 1.10, .75

son4ous [18]

Answer:

mean = 0.76

median = 0.75

range = 1.79

Step-by-step explanation:

mean = sum/no of items

for media they need to be sorted: 0.05,0.06,0.75,1.10,1.84

median is the middle item, so 0.75

range = largest item - smallest item = 1.84 - 0.05 = 1.79

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2 years ago

A certain bridge arch is in the shape of half an ellipse 106 feet wide and 33.9 feet high. At what horizontal distance from the

nata0808 [166]

Answer:

The horizontal distance from the center is 49.3883 feet

Step-by-step explanation:

The equation of an ellipse is equal to:

$\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1$

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.

Then, replacing a by 106/2 and b by 33.9, we get:

$\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1$

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

$\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883$

So, the horizontal distance from the center is 49.3883 feet

8 0

3 years ago

A boy and girl ran towards each other. The boy ran at 1 mph and the girl ran at

sergiy2304 [10]

Step-by-step Answer:

Very tricky question where we have to pay attention to units.

Total distance = D = 50 m

Total speed = S = 1+2 = 3 miles per hour

When they run towards each other for a given distance, the solution is given by

time = total distance / total speed

= 50 metres / (2+1) miles per hour.

= 50 metres / 3 miles per hour

We know that 1 inch = 2.54 cm exactly, so

D3= distance of three miles

= 3 miles

= 3 miles * 1760 yards /mile

= 3*1760 yards * 36 inches per yard

= 3*1760*36 inches * 2.54 cm / inch

= 3*1760*36*2.54 cm

= 3*1760*36*2.54 cm * (1/100) m/cm

= 3*1760*36*2.54/100 metres

The total speed is therefore

S = D/3600 seconds

= 3*1760*36*2.54/100 / 3600

= 1.34112 m/s (exactly)

Therefore time before they meet is

Time = Distance / total speed

= D / S

= 50 metres / S m/s

= 50 / 1.34112 seconds

= 37.28 seconds (to the hundredth of a second)

8 0

2 years ago

The weight of the paper clip is 1.0025 grams. Find the number of significant digits in the measurement​

The weight of the paper clip is 1.0025 grams. Find the number of significant digits in the measurement