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2 years ago

Which of the following statements is equivalent to 18+6

Mathematics

1 answer:

cricket20 [7]2 years ago

3 0

Answer:

3(6+2) is the correct answer.

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What is the slope of the line?

12345 [234]

You can find the slope using the following formula:

$\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ where\colon \\ (x1,y1)=(0,2) \\ (x2,y2)=(1,0) \\ m=\frac{0-2}{1-0}=\frac{-2}{1}=-2 \end{gathered}$

8 0

1 year ago

Given the following functions f(x) and g(x), solve (f + g)(5) and select the correct answer below: f(x)=2x^2-10 g(x)=x+9

steposvetlana [31]

Answer:

$\large\boxed{(f+g)(5)=54}$

Step-by-step explanation:

$f(x)=2x^2-10,\ g(x)=x+9\\\\(f+g)(x)=f(x)+g(x)\\\\\text{Substitute:}\\\\(f+g)(x)=(2x^2-10)+(x+9)=2x^2-10+x+9=2x^2+x+(-10+9)\\\\(f+g)(x)=2x^2+x-1\\\\(f+g)(x)(5)\to\text{put x = 5 to the equation of the function:}\\\\(f+g)(5)=2(5^2)+5-1=2(25)+5-1=50+5-1=54$

8 0

3 years ago

Which of the following statements are true about the graph below? Select all that apply

madreJ [45]

I don’t know because it wouldn’t pop up

8 0

2 years ago

An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i

Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = $\sqrt{(15-x)^2+1^2}$

The total time, 't', is given as follows;

$t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}$

The minimum value of 't' is found by differentiating with an online tool, as follows;

$\dfrac{dt}{dx} = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} = \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }$

At the maximum/minimum point, we have;

$\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0$

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

$t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89$

Therefore, the distance to run, x ≈ 14.96 mile

6 0

3 years ago

Q1.The cost of $16.50 for the music was reduction of 12% on the original cost.

NNADVOKAT [17]

Q1) £16.50 x 1.12 = £18.48
Q2)

2+9+1= 12
3h 33m = 213m
213/12 = 17.75
2x17.75 = 35.5 (music)
9x17.75 = 159.75 (films)
1x17.75 = 17.75 (books)

So it’s 159.75 minutes for the films to download

7 0

3 years ago