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LekaFEV [45]
3 years ago
7

For which value of x does f(x)=2

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

when x= -4 ,f(x)=2

Step-by-step explanation:

the coordinate in which f(x) i.e y=2 is (-4,2)

thus x= -4

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The figure shows a pair of parallel line segmants on a coordinant grid. the line segments are translated 2 units to the left to
Nitella [24]

It is D because the segments don’t intersect and are just moving 2 units to the left. They are the same distance apart.

Hope it helps and is correct :)

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3 years ago
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Amount in Account
cluponka [151]

Answer:

The answer would be B

Step-by-step explanation:

Your mean is 602.4, and your median is 609

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3 years ago
Identify the range of the function shown in the graph.<br>​
AlladinOne [14]

Answer:

C.

Step-by-step explanation:

Range is the y-values. Since our max and min for y-values is 5 and -5, respectively, our answer is C.

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4 years ago
A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height
Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

y(t)=43t-23t^{2}

B) Instantaneous Velocity at t = 1

y(1) = 43(1)-23(1)^2 = 20

A) Formula:

Average velocity =

\displaystyle\frac{\text{Displacement}}{\text{Time}}

1) 0.01

y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}

2) 0.005 s

y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}

3) 0.002 s

y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}

4) 0.001 s

y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}

3 0
3 years ago
Which shows the dimensions of two rectangular prisms that have volumes of 72 cm3 but different surface areas? A. 6 cm by 3 cm by
Nookie1986 [14]
To solve, lets find the volumes of all of the options...

V=l*w*h

A. 
6*3*4=72cm³
12*2*3=72cm³

B.
2*4*9=72cm³
9*4*2=72cm³

C.
3*3*8=72cm³
2*6*8=96cm³

D.
6*3*4=72cm³
9*4*3=108cm³

We can conclude that C & D aren't the answer, since they contain prisms that don't have a volume of 72cm³.

Now lets solve for the surface area of A and B...

A. 
sA=2(wh+lw+lh)=2(6*3+4*6+4*3)=2(18+24+12)=2(54)=108cm²
sA=2(wh+lw+lh)=2(12*2+3*12+3*2)=2(24+36+6)=2(56)=112cm²


B.
sA=2(wh+lw+lh)=2(2*4+9*2+9*4)=2(8+18+36)=2(62)=124cm²
sA=2(wh+lw+lh)=2(9*4+2*9+2*4)=2(36+18+8)=2(62)=124cm²

A is the only option with both similar volumes of 72cm³ and different surface areas...

Answer=A
3 0
3 years ago
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