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LekaFEV [45]
3 years ago
7

For which value of x does f(x)=2

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

when x= -4 ,f(x)=2

Step-by-step explanation:

the coordinate in which f(x) i.e y=2 is (-4,2)

thus x= -4

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Which is the more reasonable measurement of the distance between the tracks on a railroad:
nataly862011 [7]

If you're comparing 1.435 * 10^(-3) mm to 1.435 * 10^3 mm, then the more reasonable measurement is 1.435 * 10^3 mm since,

1.435 * 10^3 mm = 1435 mm = 1.435 meters

1 meter is about 3.28 feet approximately

So 1.435 meters is slightly larger (about 4.708 feet) which is a fairly reasonable distance between the tracks on a railroad.

-------------------

Something like 1.435 * 10^(-3) mm is equal to 0.001435 mm, which is far less than 1 mm.

6 0
3 years ago
What are the intercepts of the function?
snow_tiger [21]

Answer:

x-int: (-1, 0), (-11, 0)

y-int: (0, 11)

Step-by-step explanation:

To find x-int, set equation equal to 0:

x² + 12x + 11

(x + 1)(x + 11)

x = -11, -1

To find y-int, set <em>x</em> = 0

f(0) = 0² + 12(0) = 11

f(0) = 11

7 0
3 years ago
Is the binomial a factor of the polynomial function?
olchik [2.2K]

Answer:

YES

NO

NO

Step-by-step explanation:

The given polynomial is: $ f(x) =  x^3 + 4x^2 - 25x - 100 $

(x - a) is a factor of a polynomial iff x = a is a solution to the polynomial.

To check if (x - 5) is a factor of the polynomial f(x), we substitute x = 5 and check if it satisfies the equation.

∴ f(5) = 5³ + 4(5)² - 25(5) - 100

        = 125 + 100 - 125 - 100

        = 225 - 225

        = 0

We see, x = 5 satisfies f(x). So, (x - 5) is a factor to the polynomial.

Now, to check (x + 2) is a factor.

i.e., to check x = - 2 satisfies f(x) or not.

f(-2) = (-2)³ + 4(-2)² - 25(-2) - 100

      = -8 + 16 + 50 - 100

     = -108 + 66

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Therefore, (x  + 2) is not a factor of f(x).

To check (x - 4) is a factor.

∴ f(4) = 4³ + 4(4)² - 25(4) - 100

        = 64 + 64 - 100 - 100

        = 128 - 200

        ≠ 0

Therefore, (x - 4) is not a factor of f(x).

7 0
3 years ago
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Answer:

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